Answer:
ΔF = 0.21 N
Explanation:
For this exercise that does not ask for the change in weight we must use the law of universal gravitation
F = G M m / r²
where r is the distance from the center of the Earth, in the lower part of the building is
r =
for the upper part of the building h = 1 mile = 1609.34 m
r =R_{e} + h
the weight or the force of attraction of gravity on the floor is F = 817 N, therefore the equation remains
817 = (G M m / R_{e}²)
let's find this force for the top of the building
F` = G M m / (R_{e} + h)²
let's take out R_{e} common factor
F ’= (G M m / R_{e}²) 1 / (1 + h / R_{e})²2
F ’= (G M m R_{e}²) (1 + h / R_{e})⁻²
as the quantity h /R_{e} = 1609 / 6.37 10⁶ << 1 we can make a series space
(1 + x)⁻² = 1 -2 x + ...
we substitute
F ’= (GMm /R_{e}²) (1 - 2 1609 / 6.37 10⁶)
F ’= (GMm /R_{e}²) (1 - 2.53 10⁻⁴) = (GMm / R_{e}²) 0.99974
F ’= 817 0.99974
F ’= 816.79 N
weight Change
ΔF = ΔW = 817 - 816.79
ΔF = 0.21 N
as we see this is a very small amount
Answer:
Space Probe
Explanation:
It is actually a type of satellite to explore space considering the useful dimensions for discoveries and observations that are useful for existence of life. It collects data and returns back to the base with records that are purpose of flight.
Answer:
Explanation:
given,
mass of neutron = 1.675 × 10⁻²⁷ kg
1 kg = 5.58 × 10³⁵ eV/c²
a) mass of proton = 1.675 × 10⁻²⁷ × 5.58 × 10³⁵ = 9.34 × 10⁸ eV/c²
b) mass of electron = 9.109 x 10⁻³¹ × 5.58 × 10³⁵ = 5.08 × 10⁵eV/c²
c) mass of hydrogen = 1.675 × 10⁻²⁷ × 5.58 × 10³⁵ = 9.34 × 10⁸ eV/c²
Answer:
Reduction of order delivery times.
More efficient order fulfilment.
Lower number of incomplete orders.
Improved service in emergency situations.
Reduction of errors in the composition of orders and deliveries.
Better management of internal quality levels.
Greater flexibility (wider range of services on offer to the client)
Explanation:
Because if we don't you'll be hungry, if you don't eat for about a month you'll die