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puteri [66]
3 years ago
5

Find the following: i dont know what else to put

Mathematics
1 answer:
Luden [163]3 years ago
7 0

Answer:

0

(1/3)x+13/3

5

Step-by-step explanation:

1. Like any function, <em>g</em> takes numbers from it's domain (-8, -3, 0, 7), and transforms them into numbers in it's range (8, 6, -3, 3). <em>g</em>^-1, it's inverse, maps back from the range into the domain. Since <em>g</em> maps 0 onto -3, g^-1 must turn -3 back to 0

g(0)=-3 == g`(-3)=0

2. To find the inverse of <em>h</em>, let h(x)=y.

Now, <em>y</em><em>=</em><em>3</em><em>x</em><em>-</em><em>1</em><em>3</em>

Remember that the inverse maps from the range (the y values) back to the domain (the x's), We want the function that takes a <em>y</em> and turns it into an <em>x</em><em>.</em><em> </em>For this, we must solve for x.

From above, <em>y</em><em>/</em><em>3</em><em>+</em><em>1</em><em>3</em><em>/</em><em>3</em><em>=</em><em>x</em>

Now that we rearranged <em>h</em>, we must flip the x and y to get the inverse. This happens because the range of <em>h</em> acts as the domain for <em>h</em><em>^</em>-1

3. The function <em>h</em> will turn 5 to some unknown number. Let's call it w. Then, if you pass w to h^-1, it will be turned back to a 5.

This is equivalent to computing the functions in the reverse order, or writing the composite, which results in x=y, and then computing

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
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Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of m and the second line has a slope of \frac{1}{-m}.

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

5x - 2y = -6

-2y = -5x - 6

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We now know that m = \frac{5}{2} for the first line, which means that the slope of the second line is m = \frac{-2}{5}. With this, we have the following equation for our new line:

y = \frac{-2}{5}x + C

where C is the Y-intercept that we now need to determine with the coordinates given in the problem statement, (5, -4):

y = \frac{-2}{5}x + C

(-4) = \frac{-2}{5}(5) + C

-4 = -2 + C

C = -2

Finally, we can create our line:

y = \frac{-2}{5}x - 2

5y = -2x - 10

2x + 5y = -10

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Step-by-step explanation:

We need the measure of < g.

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Step-by-step explanation:

Hope it helps :)

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