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Elena L [17]
2 years ago
14

In the American version of the Game Roulette, a wheel has 18 black slots, 18 red slots and 2 green slots. All slots are the same

size. A person can wager on either red or black. Green is reserved for the house. If a player wagers $5 on either red or black and that color comes up, they win $10 otherwise they lose their wager. What is the expected value of playing the game once
Mathematics
1 answer:
m_a_m_a [10]2 years ago
5 0

Answer:

-$0.26

Step-by-step explanation:

Calculation to determine the expected value of playing the game once

Expected value= [18/(18+18+2) x $5)]- [20/(18+18+2) x $5]

Expected value= ($18/38 x $5) - (20/38 x $5)

Expected value= ($2.37-$2.63)

Expected value= -$0.26

Therefore the expected value of playing the game once is -$0.26

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 2,000, 200 and 20 are similar except for the number of zeros.
You can remove a zero from each to equal the number of zeros in the divisor.  So 80,000 ÷ 2,000 is equivalent to 80 ÷ 2 = 40  you just remove the 3 zeros
80,000 ÷ 200 is equivalent to 800 ÷ 2 = 400 you just keep removing 0s like for instance this time it was 2 lastly 80,000 ÷ 20 only allows us to remove 1 zero 8,000 ÷ 2 = 4,000. The smaller the divisor the greater the quotient when dividing the same number like for instance in this example 80,000
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An employee is paid a salary of \$73,840 per year, plus benefits and overtime (time and a half) on hours worked over 40 per week
gulaghasi [49]

Answer:

B. $35.50/hr and \$6,079.38 in total income

Step-by-step explanation:

Given the following :

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$73840 / 52 = $1420

Regular hours = 40

Regular earning per week = $1420

Regular earning per hour = $1420 / 40

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Number of overtime hours :

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