That would be C, D, E and F.
There should be 3 more girls than boys in the class (9 boys, 12 girls)
You want to draw 2 kings from a 52 card deck. And you do it with replacement.
There are 4 kings in a standard deck. The probability of getting one of them is
4/52 on the first draw.
For the second draw the probability is the same.
4/52
The probability for both happening is
(4/52)*(4/52) = (1/13)*(1/13) = 1/169 = 0.001597
A, D and E are correct
given ( x - 4 ) is a factor then x = 4 is a root
the remainder on division by (x - 4 ) = 0 as indicated by the 0 on the right side of the quotient
(x - 4 ) is a factor of 3x² - 13x + 4 → A
the number 4is a root of f(x) = 3x² - 13x + 4 → D ( explained above )
thus 3x² - 13x + 4 ÷ (x - 4 ) = 3x - 1 → E
the quotient line 3 - 1 0
3 and - 1 are the coefficients of the linear quotient and 0 is the remainder
