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Lana71 [14]
4 years ago
7

Su now wants to modify the text box that contains her numbered list. She accesses the Format Shape pane. In what ways can Su mod

ify the text box using the pane? Check all that apply.
A.She can rotate the text box.
B.She can add color to the text box.
C.She can add a shape to the text box.
D.She can add a border to the text box.
E.She can insert a picture in the text box.
Computers and Technology
2 answers:
Fiesta28 [93]4 years ago
7 0
I believe its E she can insert a picture in the text book
Ganezh [65]4 years ago
7 0

Answer:

Explanation:

One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.

Fill a rectangular baking glass dish with water.

Place a plastic bag with ice in the water near the left edge of the dish.

Place a lighted lamp near the left edge of the dish so that its light falls directly on the plastic bag.

Put a few drops of ink in the water.

The student did not observe any circulation of ink in the water as expected because the experiment had a flaw. Which of these statements best describes the flaw in the experiment? (2 points)

Not enough ink was added.

Not enough water was taken.

The dish was too small for the experiment.

The lamp and the ice bag were at the same place.

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Instructions
e-lub [12.9K]

Answer:

See explaination

Explanation:

dateType.h

#ifndef dateType_H

#define dateType_H

class dateType

{

public:

void setDate(int month, int day, int year);

//Function to set the date.

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day;

// dYear = year

int getDay() const;

//Function to return the day.

//Postcondition: The value of dDay is returned.

int getMonth() const;

//Function to return the month.

//Postcondition: The value of dMonth is returned.

int getYear() const;

//Function to return the year.

//Postcondition: The value of dYear is returned.

void printDate() const;

//Function to output the date in the form mm-dd-yyyy.

void isLeapYear() const;

dateType(int month = 1, int day = 1, int year = 1900);

//Constructor to set the date

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day; dYear = year;

// If no values are specified, the default

// values are used to initialize the member

// variables.

private:

int dMonth; //variable to store the month

int dDay; //variable to store the day

int dYear; //variable to store the year

};

#endif

dateType.cpp

#include <iostream>

#include "dateType.h"

using namespace std;

void dateType::setDate(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

int dateType::getDay() const

{

return dDay;

}

int dateType::getMonth() const

{

return dMonth;

}

int dateType::getYear() const

{

return dYear;

}

void dateType::printDate() const

{

cout << dMonth << "-" << dDay << "-" << dYear;

}

void dateType::isLeapYear() const

{

if ( dYear%400 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%100 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%4 == 0 )

cout<<endl<<dYear<< " is leap year.\n";

else

cout<<endl<<dYear<< " is not leap year.\n";

}

//Constructor with parameters

dateType::dateType(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

main.cpp

#include<iostream>

#include "dateType.h"

using namespace std;

int main()

{

dateType *dt1=new dateType();

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

dateType *dt2=new dateType(11,14,2019);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt2->setDate(13,32,2016);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt1->setDate(10,10,198);

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

system("pause");

return 0;

}

6 0
3 years ago
Aurelia is designing a user interface for a new game app. Which of the following should she taken into consideration for the use
serious [3.7K]

Answer:

C

Explanation:

what types of loop will be used.

4 0
3 years ago
The question is provided in the image below.
Vladimir [108]

Answer: b

Explanation:

3 0
2 years ago
How does the actual amount left to spend differ from the budgeted amount for the remaining three months of the project
Studentka2010 [4]

Answer:

What is left at any instance of the project duration can be less than the budgeted sum? And if this is the situation then we need to calculate the over expense%, and which is:

oe%= ((Actual remaining *- Budgeted)/Budgeted)*100

And this gives us the amount by which the project is now lacking in the budget. However, project managers in the start itself assign some value for this, and hence this deficit does not create the problem at any time. And deficit occurs due to resources going down or falling ill. Or there can be an unwanted bug that requires more time.

Explanation:

Please check the answer.

3 0
4 years ago
Write a program to print sum on first 10 natural numbers.
Kamila [148]

sum of 10 natural number is 55

4 0
3 years ago
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