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Marta_Voda [28]
3 years ago
6

Three students, Linda, Tuan, and Javier, are given five laboratory rats each for a nutritional experiment. Each rat’s weight is

recorded in grams. Linda feeds her rats Formula A, Tuan feeds his rats Formula B, and Javier feeds his rats Formula C. At the end of a specified time period, each rat is weighed again and the net gain in grams is recorded. Determine whether or not the variance in weight gain is statistically the same among Javier’s and Linda’s rats. Test at a significance level of 10%. What is the alternative hypothesis?

Mathematics
1 answer:
prohojiy [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Hello!

You have the information of the net gain of weight of rats of three independent groups that were fed with three different formulas (A, B and C)

The objective is to determine if the population variance of the weight gain of the rats fed with formula C (feed by Javier) is the same as the population variance of the weight gain of the rats fed with formula A (feed by Linda)

Then you have two variables of interest:

X₁: Net weight gain of the rats fed with formula A (gr)

X₂: Net weight gain of the rats fed with formula C (gr)

Assuming that both variables have a normal distribution, the statistical test for this analysis is a variance ratio.

The hypotheses are:

H₀: σ₁²=σ₂²

H₁: σ₁²≠σ₂²

α: 0.10

F= \frac{S_1^2}{S_2^2} * \frac{Sigma_1^2}{Sigma_2^2}~~F_{n_1-1;n_2-1}

The sample variances are:

S₁²= 10.09gr

S₂²= 27.16

F_{H_0}= \frac{10.09}{27.16} *1= 0.37

  • <em>Remember, another way of expressing the statistical hypotheses for this test is H₀: σ₁²/σ₂²= 1 vs. H₁: σ₁²/σ₂²≠ 1, the theoretical value for the ration of the population variances is one (considering that the null hypothesis is true).</em>

The p-value of the test is 0.3605

Using the p.value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value is greater than α, the decision is to not reject the null hypothesis.

Using a level of 10%, there is no significant evidence to reject the null hypothesis. Then you can conclude that the population variance of the net weight gain of the rats fed by Javier is statistically the same as the population net weight gain of the rats fed by Linda.

I hope this helps!

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Answer:

see explanation

Step-by-step explanation:

the sum of the 3 angles in a triangle = 180°

Summing the 3 angles and equating to 180 gives

2x + 3 + 4x + 2 + 2x - 1 = 180

8x + 4 = 180 ( subtract 4 from both sides )

8x = 176 ( divide both sides by 8 )

x = 22

∠A = 2x + 3 = (2 × 22) + 3 = 44 + 3 = 47°

∠B = 4x + 2 = (4 × 22) + 2 = 88 + 2 = 90°

∠C = 2x - 1 = (2 × 22) - 1 = 44 - 1 = 43°


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3 years ago
Ashley is digging for rocks at a geological site. She has 140 meters of rope and 4 stakes to mark off a rectangular area. Which
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Answer:

C

Step-by-step explanation:

Let's go through each set of dimensions and test them. Keep in mind that two times the sum of the length and width of a rectangle yields the perimeter.

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B) 2(70+70)=2(140)=280

C) 2(60+10)=2(70)=140

Therefore, the correct answer is C. Hope this helps!

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A farm stand sells apples pies and jars of applesauce. The table shows the number of apples needed to
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98/ 18

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Determine la ecuación general de la recta que pasa por los puntos (1,4); (- 2, - 5) y grafíquela.
Rudiy27

The equation of the line that passes through the points (1 , 4) and (-2, -5) is y = 3x + 1

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed {m = \frac{y_2 - y_1}{x_2 - x_1}} }

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )} }

Let us tackle the problem.

Let :

(1 , 4) → (x₁ , y₁)

(-2, -5) → (x₂ , y₂)

To find the straight line equation, the following formula can be used :

\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}

\frac{y - 4}{-5 - 4} = \frac{x - 1}{-2 - 1}

\frac{y - 4}{-9} = \frac{x - 1}{-3}

\frac{y - 4}{3} = \frac{x - 1}{1}

y - 4 = 3 ( x - 1 )

y = 3x - 3 + 4

\large {\boxed {y = 3x + 1} }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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4 years ago
You take a trip to downtown Boston to walk the Freedom Trail with your family. After you walk through the Bunker Hill Memorial,
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Full question:

Linear Functions: Taking a Taxi

You take a trip to downtown Boston to walk the Freedom Trail with your family. After you walk through the Bunker Hill Memorial, your family decides to take a taxi to a restaurant for dinner. After 1 mile, the meter on the taxi says $4.75. It will cost $8.25 to go 3 miles. The cost varies linearly with the distance that you traveled. If you have $11 in your pocket, will you be able to take the cab 5 miles?

Answer:

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Step-by-step explanation:

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y=4.5*5

y= $22.5

Therefore we cannot go 5 miles just having $11

3 0
3 years ago
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