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Alekssandra [29.7K]
3 years ago
8

The pacefic ocean has a surface area of about 166 241 700km^2 and an average depth of 3940 m. Estimate the volume of the Pacific

ocean in cubic centimetres
Physics
1 answer:
posledela3 years ago
6 0

Answer:

\lim_{(x,y) \to \(0,0)}    \frac{2x {y}^{2} }{ {x}^{2}  {y}^{2} }

Explanation:

\lim_{(x,y) \to \(0,0)}

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Light traveling from water to a gemstone strikes the surface at an angle of 80.0º and has an angle of refraction of 15.2º . (a)
7nadin3 [17]

Answer:

a

The the speed of light in the gemstone is  v= 0.599*10^8 m/s

b

The unreasonable thing about this is that the speed of ligth in the gemstone is too low

the speed is 19% of the speed of light  which is very low

c

One main unreasonable or inconsistent factor is that the assumption that the  differnce between the angle of incidence and angle of refraction is  very large

Explanation:

  From the question we are told that

       The  angle of incidence  i = 80^o

        The angle of refraction  r = 15.2^o

From Snell's law we have ,

      n_1 sin \theta_1 = n_2 sin \theta_2

    Where n_1 is the refractive index of the first medium (water) with a constant value  of  n_1 = 1..333

                n_2  is the refractive index of the second medium (gem stone)

                 \theta_1 is the angle between  the beam and perpendicular surface of the first medium

               \theta_2  is the angle  between the beam an the perpendicular surface of the second medium

      Making  the n_2 the subject of the formula

                       n_2 = n_1 \frac{sin \theta_1}{sin \theta_2}

                           = (1.333)(\frac{sin (80.0)}{sin  15.2} )

                           = 5.007

 Generally refractive index of a material  is mathematically represented

                      n = \frac{c}{v}

 Where c is the speed light

               v is the speed of light  observed in a medium

 Making v the subject

            v = \frac{c}{n}

 substituting value for gem stone

          v  =  \frac{3.0*10^8}{5.007}

              v= 0.599*10^8 m/s

     

               

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