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mixer [17]
3 years ago
8

Numbers in exponential form

Physics
1 answer:
kaheart [24]3 years ago
5 0
Do the same thing you were doing
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The kinetic and potential energies of an object both always depend on which property?.
hichkok12 [17]

Answer:

the object's position.

Explanation: might help ion know

5 0
3 years ago
a wrench weighs 5.24 newtons on earth. when it is taken to the Moon, where g =1.16 m/s2 how much does it weigh?
Andrew [12]

“Weight of the wrench” on “the moon” is “6.07 kg”.

<u>Explanation</u>:

Weight of the wrench is 5.24 N  

Weight of the wrench in kilograms = W × g

Taken “g” on the moon is 1.16 \mathrm{m} / \mathrm{s}^{2}

=5.24 \mathrm{N} \times 9.81 \mathrm{m} / \mathrm{s}^{2}=51.352 \mathrm{kg}

Weight of the wrench in kilograms is 51.352 kg.

Formula to calculate weight of the object on the moon is

\frac{\text {weight of the object on earth}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}

Substitute the values given,

=\frac{51.352 \mathrm{kg}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}

=5.234 \times 1.16

= 6.07 kg

Therefore, weight of the wrench on the moon is 6.07 kg.  

6 0
3 years ago
Can somebody please answer this correctly I will give brainliest
vodka [1.7K]
I think what’s wrong is that the paper clip isn’t connecting to the other thing on the bottom
8 0
3 years ago
What are the approximate dimensions of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 27
gayaneshka [121]

Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

                   θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

                 

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

                         s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

                          s_700 = 29.4 m

8 0
4 years ago
A An ____ occurs when a very low resistance circuit is formed and can easily start a fire.
Andrews [41]

Answer:

1- Short circuit

2- ammeter

6 0
3 years ago
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