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Oksi-84 [34.3K]
3 years ago
15

What is the vertex?? Please answer QUICK!

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

D

Step-by-step explanation:

To obtain vertex form from the given equation use the method of completing the square

given 8y + x² = - y² - 181 + 26x

rearrange having the x terms and y terms together

add y² to both sides

8y + x² + y² = - 181 + 26x ( subtract 26x from both sides )

x² - 26x + y² + 8y = - 181

add (half the coefficient of the x/y terms )² to both sides

x² + 2(- 13)x + 169 +y² + 2(4)y + 16 = - 181 + 169 + 16

completing the square on both the x and y terms

(x - 13)² + (y + 4)² = 4 → D


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Answer:You already answer the question what is there to answer again?

Step-by-step explanation:

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What is radiant energy from the sun called
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1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co
Olenka [21]

Answer:

g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\

Step-by-step explanation:

First, notice that:

g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\

g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\

g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\

We proceed to use the chain rule to find g_{r}(\sqrt{2},\frac{\pi}{4}) using the fact that X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta) to find their derivatives:

g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\

Because we know X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta) then:

\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)

We substitute in what we had:

g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)

Now we put in the values r=\sqrt{2}\ and\ \theta=\frac{\pi}{4} in the formula:

g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})

Because of what we supposed:

g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})

And we operate to discover that:

g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}

g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}

and this will be our answer

3 0
3 years ago
What would be the answer?
zmey [24]

Answer:

6

Step-by-step explanation:

To breakeven means that you made exactly as much money as you spent, so if you spent $50 to make lemonade, you would need to make $50 in profits from selling to break even

first subtract the cost of making each horse from the price of selling each horse (you do this to find out how much profits he makes from one horse):

125 - 75 = 50

now divide 300 by 50 to find out how many horses need to be made to break even:

300 ÷ 50 = 6

6 0
3 years ago
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