Question

A 20% apple juice drink is mixed with a 100% apple juice drink. The function f(x)=(2)(1.0)+x(0.2)2+x models the concentration of apple juice in the drink after x gallons of the 20% drink are added to 2 gallons of pure juice. What will be the concentration of apple juice in the drink if 6 gallons of 20% drink are added? Give the answer as a percent but do not include the percent sign (%).

Answer 1

Answer:

17.5

Step-by-step explanation:

Given that:

20% apple juice drink is mixed with a 100% apple juice drink.

$f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}$

represents the concentration of apple juice in the drink when $x$ gallons of 20% drink are added to 2 gallons of pure juice.

Also, given that 6 gallons of 20% drink are added to the 2 gallons of pure juice.

To find:

The concentration of apple juice in the drink = ?

Solution:

Given the function:

$f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}$

and

$x=6\ gallons$

$f(x)=\dfrac{(2)(0.1)+6(0.2)}{2+6}\\\Rightarrow f(x)=\dfrac{0.2+1.2}{8}\\\Rightarrow f(x)=\dfrac{1.4}{8}\\\Rightarrow f(x)=\bold{0.175}$

In percentage, the concentration 17.5.