Question

Which choice shows a function with a domain of {–4, –2, 2, 4}? On a coordinate plane, a vertical line is at x = 2. On a coordinate plane, a line goes through (negative 2, negative 2) and (0, negative 3). {(–4, 2), ( –2, 1), (2, 0), (4, 5)} {(1, –4), (0, –2), (2, 2), (6, 4)}

Answer 1

Answer:

$\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}$

Step-by-step explanation:

Given: Domain of function is $\left \{ -4,-2,2,4 \right \}$

To find: the function that has domain $\left \{ -4,-2,2,4 \right \}$

Solution:

A function is a relation in which every element of the domain has a unique image in the co-domain.

For x = 2, domain is $\left \{2 \right \}\neq \left \{ -4,-2,2,4 \right \}$

For a line that passes through $(-2,-2)\,,\,(0,-3)$,

domain must have 0 but $0\notin \left \{ -4,-2,2,4 \right \}$

Domain of $\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}$ is $\left \{ -4,-2,2,4 \right \}$

Domain of $\left \{ (1, -4), (0, -2), (2, 2), (6, 4) \right \}$ is $\left \{ 1,0,2,6 \right \} \neq \left \{ -4,-2,2,4 \right \}$

So, answer is $\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}$