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Inessa05 [86]
1 year ago
10

The principal represents an amount of money deposited in a savings account subject to

Mathematics
1 answer:
RSB [31]1 year ago
3 0

Step-by-step explanation:

So the general formula for compound interest is A = P(1+\frac{r}{n})^{nt} where t is typically time in years, and n is how many times it's compounded per year. But in this case it's only compounded 1 time per year so the equation is just A = P(1+r)^t. in this case P is the principal amount, r is the interest, and A is the final amount. So the 5% interest rate becomes 0.05 by dividing by 100 to convert it into decimal form and the principle amount of 11,000. This gives you the formula A = 11000(1.05)^t. This is the answer to the first question where t is the time in years. When it says "Find interest earned" I'm a bit confused, is it giving you x amount of years where you have to calculate the interest earned or does it want a general equation? Because the general equation would be the final amount - the principle amount which calculates the difference. So the equation for interest earned would be 11000(1.05)^t-11000. To calculate the amount of money after 5 years you simply plug in 5 as t. this gives you the equation 11000(1.05)^5 \approx 11000(1.276) \approx 14,039.10

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Geometry help please! Match the reasons with the statements.
SSSSS [86.1K]

Given:

∠PRS and ∠VUW are supplementary.

To prove:

Line TV || Line QS

Solution:

Step 1: Given

∠PRS and ∠VUW are supplementary.

Step 2: By the definition of supplementary angles

m\angle {PRS}+m\angle {VUW}=180^{\circ}

Step 3: Angles forming a linear pair sum to 180°

m\angle {PRS}+m\angle {SRU}=180^{\circ}

Step 4: By transitive property of equality

step 2 = step 3

m\angle {PRS}+m\angle {VUW}=m\angle {PRS}+m\angle {SRU}

Step 5: By algebra cancel the common terms in both side.

{m} \angle {VUW}={m} \angle{SRU}

Step 6: By converse of corresponding angles postulate

Line TV || Line QS

Hence proved.

6 0
3 years ago
Which step in the proof has a flow?
Dmitry [639]

Answer:

Reason 2

Step-by-step explanation:

The reason should be transitive property( if a=b and b=c then a=c) not reflective property.

7 0
3 years ago
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation t
horrorfan [7]

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

\left[\begin{array}{ccc}4\\3\end{array}\right]

The transformation Matrix is:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]

The image of the vector after applying the transformation will be:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]

The correct option is C

7 0
3 years ago
4 * x² - (6+y) when x = -2 and y = -9​
aalyn [17]

Answer:

4 * (-2)^2 - (6+(-9))

= 4 * 4 - (-3)

= 16 - (-3)

= 16 + 3

= 19

8 0
2 years ago
←<br><br> How many solutions does this linear system have<br> y =<br> x+2<br> 6x - 4y = -10
defon

Answer:

This linear system has one solution.

Step-by-step explanation:

First equation: y = x + 2

Second equation: 6x - 4y = -10

Let's change the second equation in slope-intercept form y = mx + b.

<u>Slope-intercept form</u>

y = mx + b

m ... slope

b ... y-intercept

6x - 4y = -10

6x + 10 = 4y

\frac{6}{4}x + \frac{10}{4} = y

\frac{3}{2}x + \frac{5}{2} = y

If two lines have the <em>same slope </em>but <em>different y-intercept</em>, they are parallel - <u>system has no solutions</u>.

If two lines have the <em>same slope</em> and the <em>same y-intercept</em>, they are the same line and are intersecting in infinite many points - <u>system has infinite many solutions</u>.

If two lines have <em>different slopes</em> then they intersect in one point - <u>system has one solution</u>.

We see that lines have different slopes. First line has slope 1 and the other line has slope \frac{3}{2}. So the system has one solution.

You can also check this by solving the system.

Substitute y in second equation with y from first.

6x - 4y = -10

6x - 4(x + 2) = -10

Solve for x.

6x - 4x - 8 = -10

2x = -2

x = -1

y = x + 2

y = -1 + 2

y = 1

The lines intersect in point (-1, 1). <-- one solution

8 0
1 year ago
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