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crimeas [40]
2 years ago
15

Graph the line that contains the point (o,3) and has a slope of 1/2

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
3 0

Answer:

Step-by-step explanation:

y-3=1/2(x-0)=1/2 x

2y-6=x

2y-x=6

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Daniel has 1 blue pencil and 5 yellow pencils in his backpack. He also has 2 pink erasers, 4 tan erasers, and 3 gray erasers in
Kamila [148]
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2 years ago
Find the equation of the line that passes through the point (-5,7) and is perpendicular to the line y=-x+12.
insens350 [35]

Answer:

y=x+12

Step-by-step explanation:

y=-x+12; is a line with slope m1=-1

to find perpendicular slope of intersecting line take the negative inverse of m1. so -1*(1/(-1))=1=m2

use equation for a line of y=m*x+b and put in the point (-5,7) and solve for b=the y axis intercept

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2 years ago
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4 0
3 years ago
Read 2 more answers
Write the STANDARD FORM of the equation through the point (4,-4) witha slope of -2.
boyakko [2]

The general equation of line with the slope "m" and passing points (a,b) is :

y - b = m (x -a)

In the given question:

Slope m = -2, passing points (a,b) = (4,-4)

Substitute the value of a = 4, b = -4 in the general equation of line

\begin{gathered} y-b=m(x-a) \\ y-(-4)=(-2)(x-4) \\ y+4=-2(x-4) \\ y+4=-2x+8 \\ y+2x=8-4 \\ 2x+y=4 \end{gathered}

The equation with the slope -2 and passing points (4,-4) is 2x + y = 4

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