Answer:
Project A: $55,000 Project B: $50,800 Contractor should choose project A
Step-by-step explanation:
The expected value of the project is the sum of products of profit and its probability:
In thousands, ...
A: (50×0.6) +(80×0.3) +(10×0.1) = 30 +24 +1 = 55 . . . thousand
B: (100×0.1) +(64×0.7) +(-20×0.2) = 10 +44.8 -4 = 50.8 . . . thousand
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The contractor should choose Project A based on the expected value of profit.
Answer:
y=1/2x+4
Step-by-step explanation:
Refer to the picture that given :)
Answer:
n= -9
Step-by-step explanation:
Simplifying
-2(n + 3) + -4 = 8
Reorder the terms:
-2(3 + n) + -4 = 8
(3 * -2 + n * -2) + -4 = 8
(-6 + -2n) + -4 = 8
Reorder the terms:
-6 + -4 + -2n = 8
Combine like terms: -6 + -4 = -10
-10 + -2n = 8
Solving
-10 + -2n = 8
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '10' to each side of the equation.
-10 + 10 + -2n = 8 + 10
Combine like terms: -10 + 10 = 0
0 + -2n = 8 + 10
-2n = 8 + 10
Combine like terms: 8 + 10 = 18
-2n = 18
Divide each side by '-2'.
n = -9
Simplifying
n = -9
9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.