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3 years ago

Find the length of the missing side. Leave your answer in simplest radical form.

Mathematics

1 answer:

faltersainse [42]3 years ago

5 0

It would be 13x10 then turn it into a fraction then simplify.

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An angle, θ, is in standard position. The terminal side of the angle passes through the point (4, 5).

lara31 [8.8K]

Answer:

cos Θ = $\frac{4}{\sqrt{41} }$

Step-by-step explanation:

Given the angle passes through (4, 5 ) then the right triangle with sides 4 and 5 has hypotenuse h given by

h² = 4² + 5² = 16 + 25 = 41 ( take the square root of both sides )

h = $\sqrt{41}$

In relation to Θ, 4 is adjacent and 5 is opposite, thus

cos Θ = $\frac{adjacent}{hypotenuse}$ = $\frac{4}{\sqrt{41} }$

5 0

3 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

4 years ago

Which is the quotient of 5 ÷ 1/4 ? Use the model to help. due TOMMOROW help

DaniilM [7]

The answer would be 1.25.

6 0

3 years ago

4. If Mahamat has 36 coins totaling $3.00, and the coins are all nickels and quarters, how many of each coin does he have?

MakcuM [25]

The answer is 30 i believe :) ♡

6 0

3 years ago

18c) Find the value of x in each case.

iVinArrow [24]

Answer:

x = 22.5°

Step-by-step explanation:

m∠DEA = 2x

DE || AB

m∠EAB = 2x - by Alternate Interior Angles

Exterior angle = 6x, which equals 2x + 4x

m∠BEA = 4x

Exterior Angle 4x = 2x + 2x

m∠B = 2x

2x + 4x + 2x = 180°

8x = 180°

x = 22.5°

<h2>Exterior Angles of a Triangle:</h2>

An exterior angle of a triangle is equal to the two REMOTE angles inside the triangle.

In this example, we know that 6x has remote angles of ∠EAB and ∠BEA

We found out that m∠EAB = 2x, so m∠BEA must equal 6x - 2x or 4x

<h2>Sum of angles in a Triangle:</h2>

The sum of all angles in a triangle is equal to 180°.

In this example, we found all the angles, 2x, 4x, 2x. We added all of those values to equal 8x

Since the sum of all angles = 180°:

8x = 180°

x = 180°/8

x = 22.5°

-Chetan K

8 0

3 years ago