All categories

3 years ago

Find the length of the missing side. Leave your answer in simplest radical form.

Mathematics

1 answer:

faltersainse [42]3 years ago

5 0

It would be 13x10 then turn it into a fraction then simplify.

You might be interested in

A commercial building contractor is trying to decide which of two projects to commit her company to. Project A will yield a prof

Alexxandr [17]

Answer:

Project A: $55,000 Project B: $50,800 Contractor should choose project A

Step-by-step explanation:

The expected value of the project is the sum of products of profit and its probability:

In thousands, ...

A: (50×0.6) +(80×0.3) +(10×0.1) = 30 +24 +1 = 55 . . . thousand

B: (100×0.1) +(64×0.7) +(-20×0.2) = 10 +44.8 -4 = 50.8 . . . thousand

The contractor should choose Project A based on the expected value of profit.

3 0

3 years ago

Which equation represents the proportional relationship in the table ?

den301095 [7]

C=3r

hope this helps!

3 0

3 years ago

Read 2 more answers

Write an equation of the line below.

Blizzard [7]

Answer:

y=1/2x+4

Step-by-step explanation:

Refer to the picture that given :)

4 0

3 years ago

Read 2 more answers

Solve −2(n+3)−4=8 . The solution is n= .

Anton [14]

Answer:

n= -9

Step-by-step explanation:

Simplifying

-2(n + 3) + -4 = 8

Reorder the terms:

-2(3 + n) + -4 = 8

(3 * -2 + n * -2) + -4 = 8

(-6 + -2n) + -4 = 8

Reorder the terms:

-6 + -4 + -2n = 8

Combine like terms: -6 + -4 = -10

-10 + -2n = 8

Solving

-10 + -2n = 8

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + -2n = 8 + 10

Combine like terms: -10 + 10 = 0

0 + -2n = 8 + 10

-2n = 8 + 10

Combine like terms: 8 + 10 = 18

-2n = 18

Divide each side by '-2'.

n = -9

Simplifying

n = -9

3 0

3 years ago

Help. I need help with these questions ( see image).<br> Please show workings.

Andrew [12]

9514 1404 393

Answer:

4) 6x

5) 2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

$\text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}$

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

lim[h→0](f(x+h)-f(x))/h = 2ax +b

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0

3 years ago