Triangle Q R S is shown with exterior angles. Line R Q extends through point D. Line Q R extends through point E. Line Q S exten
ds through point C.
Which angle has a measure equal to the sum of m∠SQR and m∠QRS?
∠RSC
∠SRE
∠DQS
∠QSR
Which angle has a measure equal to the sum of m∠SQR and m∠QRS?
∠RSC
∠SRE
∠DQS
∠QSR
2 answers:
Answer:
Option A.
Step-by-step explanation:
In triangle QRS, Line R Q extends through point D. Line Q R extends through point E. Line Q S extends through point C as shown below.
We need to find an angle that has a measure equal to the sum of m∠SQR and m∠QRS.
According to the exterior angle theorem, the measure of an exterior angle of a triangle is equal to the sum of measures of two opposite interior angles.
Since ∠SQR and ∠QRS are two interior angles of a triangle QRS, so ∠RSC is the exterior angle of opposite to ∠SQR and ∠QRS.
By using exterior angle theorem we conclude that
m∠RSC = m∠SQR + m∠QRS
∠RSC has a measure equal to the sum of m∠SQR and m∠QRS.
Therefore, the correct option is A.
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Answer:
Option (4)
Step-by-step explanation:
Area of a triangle =
Where a and b are the sides of a triangle and θ is the angle between the sides a and b.
By this rule,
Area of ΔWZY =
45 =
9 = (YZ).Sin(115)°
YZ =
YZ = 9.93
Perimeter of parallelogram WXYZ = WX + XY + YZ + WZ
= 9.93 + 10 + 9.93 + 10
= 39.86
≈ 40 units
Therefore, perimeter of the parallelogram is 40 units.
Option (4) is the answer.
Answer: e.
Step-by-step explanation:
1. You have the following expression given in the problem:
2. To solve the exercise and find an equal expression, you must simplify that expression. Apply the Distributive property. Multiply the terms inside the parentheses by . Then, you obtain: