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3 years ago

Someone please help me will give BRAILIEST!!!!

Mathematics

2 answers:

Semenov [28]3 years ago

7 0

That is dependent because it is changing.independent stays the same

olasank [31]3 years ago

5 0

Dependent. Mary's choices are dependent on the game pieces provided by the board game and Jason's choice are dependent on the pieces provided by the board game and the left over pieces that Mary did not choose.

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Shaun's savings can be modeled by the regression equation y = 6x^2 + 75x+200. Which of the following is the best prediction for

kipiarov [429]

Answer:

Option D

Step-by-step explanation:

The equation to predict the amount saved is

$y = 6x ^ 2 + 75x + 200.$

Assuming that the variable x represents the saving months, then substitute $x = 25$ in the quadratic equation and solve for y.

$y = 6 (25) ^ 2 +75 (25) +200\\\\y = \$\ 5,825$

The answer is the option D $5,825

3 0

3 years ago

The surface area of a typical classroom floor is closest to______.

avanturin [10]

Answer would be C. Why A would be incorrect: 100m^2 is 100m × 100 m. That would be as big as a football field. Why B would be incorrect: 1cm^2 is 1cm × 1cm. You can use a regular 15 cm to measure a piece of paper with the length of 1cm each side. Why C would be correct: 1m^2 = 1m × 1m and it is also equals to 60cm × 60 cm. A 1 meter ruler = 60 cm = 4 times of your average 15 cm ruler. So, it is reasonable that a classroom is 10m by 10m in length and breadth. Why D would be incorrect: The same explanation applies to here as well. Things that can be measured with 1m × 1m is a square table so your classroom can't be that small to fit an average of 30 to 40 students in there. I hope my explanations were detailed and easy to understand. :)

4 0

2 years ago

Read 2 more answers

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

2 years ago

what is the value of the x variable in the solution to the following system of equations? 2x 2y = 6 x 3y = −1 a. −2 b. 2 c. 5 d.

tatuchka [14]

2x + 2y = 6 . . . . . (1)
x + 3y = -1 . . . . . (2)

(1) x 3 => 6x + 6y = 18 . . . . . (3)
(2) x 2 => 2x + 6y = -2 . . . . . (4)

(3) - (4) => 4x = 20
x = 20/4 = 5

7 0

3 years ago

Can I get help please

aleksandrvk [35]

Answer:

x > -3.2

Step-by-step explanation:

6 0

3 years ago