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4 years ago

14

The 25 members of the reading club are buying a book to discuss at the next meeting the club leader got a special price the book

will cost $8.14 for each person how much will the 25 books cost

1 answer:

Pachacha [2.7K]4 years ago

5 0

Answer:

203.5

Step-by-step explanation:

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CAN SOMEONE PLS HELP ME OUT ON THIS PROBLEM?!?! PLSSS

Artyom0805 [142]

Answer:

First one: 16 units^2

Second One: 15 units^2

Step-by-step explanation:

First One:

A= $\frac{1}{2} (2)(4)(4)=16 units^2$

Second One:

$\frac{1}{2} (2)(5)(3)=15 units^2$

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3 years ago

Amy paid $68.68 for a pair of running shoes during a 35 %-off sale. What was the regular price?

Katen [24]

Answer:

original price = 105.66

Step-by-step explanation:

35% off means she pays 100-35 = 65%

original price * 65% = 68.68

Change to decimal form

original price *.65 = 68.68

Divide each side by .65

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3 years ago

Please help drag and drop

lakkis [162]

FCH - NPM

PNM - CFH

HF - MN

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3 years ago

Which rational function models the time, y, in hours, that it takes the train to travel between the two cities at an average spe

AVprozaik [17]

Answer:

$y=\frac{x}{6.4}$

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem, we have a proportional relationship between the average speed (x) and the time (y)

Find the constant of proportionality k

Fox =32, y=5

$k=\frac{5}{32}$

substitute

$y=\frac{5}{32}x$

we have

$\frac{5}{32}=\frac{1}{6.4}$

therefore

$y=\frac{x}{6.4}$

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3 years ago

Read 2 more answers

Find the x intercepts of the parabola with vertex (6,-5) and y- int (0,175)

prisoha [69]

Hmmm so.. .it could be either a horizontal or vertical parabola, let's assume or use a vertical parabola vertex equation then... namely, the squared variable being "x".

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
\begin{cases}
h=6\\
k=-5
\end{cases}\implies y=a(x-6)^2-5
\\\\\\
\textit{we also know }
\begin{cases}
x=0\\
y=175
\end{cases}\implies 175=a(0-6)^2-5\implies 180=a6^2
\\\\\\
\cfrac{180}{36}=a\implies 5=a\qquad thus\qquad \boxed{y=5(x-6)^2-5}$

$\bf \textit{at the x-intercepts, y = 0, thus }\qquad 0=5(x-6)^2-5
\\\\\\
5=5(x-6)^2\implies \cfrac{5}{5}=(x-6)^2\implies \pm\sqrt{1}=x-6
\\\\\\
\pm 1+6=x\implies x=
\begin{cases}
7\\
5
\end{cases}$

7 0

3 years ago