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MAXImum [283]
3 years ago
7

How do you solve this 4(x+1)=16 ?

Mathematics
2 answers:
Lena [83]3 years ago
5 0

Answer: Create equivalent expressions in the equation that all have equal bases, then solve for

x

x

.

x

=

−

2

Step-by-step explanation:

sattari [20]3 years ago
3 0

Answer:

x=3

Step-by-step explanation:

4(x+1)=16

4x+4=16

4x+4-4=16=4

4x=12

4x/4=12/4

x=3

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Can someone help struggling please please
ivolga24 [154]

Answer:

I don't know this math sorry!

5 0
4 years ago
Whats 1.64 as a mixed number in simplest form
raketka [301]
It is 1 16/25

Hope it helps ;-)
8 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
What’s is the length of the lower base, ZX? And Which angle has a sine ratio of 4/5?
PilotLPTM [1.2K]

1. YX = 8√3/tan60° = 8

so ZX = ZY + YX = 10 + 8 = 18

2. angle Q

8 0
3 years ago
Find the 76th term of the arithmetic sequences 16 14 12
grigory [225]

Answer:

a₇₆ = - 134

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134

7 0
3 years ago
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