Answer:
Option B. 450mL
Explanation:
To obtain the volume of water that must be added, we need to First find the volume of the diluted solution.
C1 (concentration of the stock solution) = 8M
V1 (volume of the stock solution) = 150mL
C2 (concentration of the diluted solution) = 2M
V2 (volume of the diluted solution) =?
Using the dilution formula C1V1 = C2V2, we can obtain the volume of the diluted solution as follow:
C1V1 = C2V2
8 x 150 = 2 x V2
Divide both side by 2
V2 = (8 x 150)/2
V2 = 600mL
The volume of water added is simply the difference between the volume of the diluted solution and that of the stock solution. This is illustrated below
Volume of water added = V2 - V1 = 600 - 150 = 450mL
Answer:
A.) 4.0
Explanation:
The general equilibrium expression looks like this:
![K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%7D)
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = molarity
-----> lowercase letters = balanced equation coefficients
In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.
<----- Equilibrium expression
![K = \frac{[2 M] [2 M]}{[1 M] [1 M] }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5B2%20M%5D%20%5B2%20M%5D%7D%7B%5B1%20M%5D%20%5B1%20M%5D%20%7D)
<----- Insert molarities
<----- Multiply
<----- Divide
Answer:
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Explanation:
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Answer:
Rate constant at 725 K is 
Explanation:
According to Arrhenius equation for a reaction-
where 
and 
are rate constants of reaction at 
and 
temperatures (in kelvin) respectively.
is activation energy of reaction.
Here = 600 K , = 
= 725 K, = 262 kJ/mol and R = 8.314 J/(mol.K)
So plugin all the values in the above equation-
So, =
Hence rate constant at 725 K is
Answer:
7% 4)2(10
Explanation:
beacouse if you divide it you can get the answer
