1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ANEK [815]
3 years ago
7

A compound containing 5.93% H and 94.07% O has a molecular mass of 34.02 g/mol determine the empirical and Molecular formula Of

this compound
Chemistry
1 answer:
Tom [10]3 years ago
7 0

Answer:

7% 4)2(10

Explanation:

beacouse if you divide it you can get the answer

You might be interested in
(True or false) The water molecule can be either an acid or a base. Justify.
iren [92.7K]

Answer:

TRUE!!!!

Explanation:

Water can act as both an acid and a base in solution and undergoes autoionization, where it can be both an acid and a base to itself. When mixed with an acid, water accepts hydrogen ions and acts as a base. However, when water is mixed with a base, it donates hydrogen ions and acts like an acid.

Not my words! I hope this helps :)

6 0
3 years ago
Read 2 more answers
Let us assume that fe(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented
Yuki888 [10]

17.8 mL NaOH

<em>Step 1.</em> Write the chemical equation

Fe^(2+) + 2NaOH → Fe(OH)2 + 2Na^(+)

<em>Step 2.</em> Calculate the moles of Fe^(2+)

Moles of Fe^(2+) = 500 mL Fe^(2+) × [0.0230 mmol Fe^(2+)]/[1 mL Fe^(2+)]

= 11.50 mmol Fe^(2+)

<em>Step 3.</em> Calculate the moles of NaOH

Moles of NaOH = 11.50 mmol Fe^(2+) × [2 mmol NaOH]/[1 mmol Fe^(2+)]

= 23.00 mmol NaOH

<em>Step 4.</em> Calculate the volume of NaOH

Volume of NaOH = 23.00 mmol NaOH × (1 mL NaOH/1.29 mmol NaOH)

= 17.8 mL NaOH

3 0
4 years ago
NEED HELP NOW
sertanlavr [38]

Answer:

you need to use the of the five to the report to the report that there are two different and the other two are the same limited as the or the two of the 8

Explanation:

get

5 0
3 years ago
You can increase the surface area of a block of ice by
lozanna [386]
Surface area<span> of a solid object is a measure of the total </span>area<span> that is occupied by the surface of object. 

If two objects has same mass, then smaller size particles will have greater surface area. 

Thus, in order to increase the surface area of ice, one can crush it into small particles. Due to crushing, particles will break into smaller size and eventually this will result in larger surface area.  </span>
3 0
3 years ago
A 36.2 g object has a heat capacity of 12.5 J/ oC. How much energy (in J) is required to raise the temperature by 5.73 oC?
iren2701 [21]

Answer:

\Delta H=2592.825\ J

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of object = 36.2 g

Specific heat = 12.5 J/g°C

\Delta T=5.73\ ^0C

So,  

\Delta H=36.2\times 12.5\times 5.73\ J=2592.825\ J

\Delta H=2592.825\ J

7 0
3 years ago
Read 2 more answers
Other questions:
  • Choose all the answers that apply.
    14·2 answers
  • n unknown weak acid, HA, it titrated with 0.6 M NaOH. The pH at the halfway point of this titration was found to be 4.215. If th
    10·1 answer
  • How do bears, birds, invertebrates and trees each benefit from the presence of salmon?
    7·1 answer
  • Anabolic reactions means?​
    5·1 answer
  • Evan and his friends are working on a group project on matter. Michelle says that matter is anything that has mass. Ricky says m
    14·1 answer
  • PLEASE ANSWER
    7·1 answer
  • For the covalent compound P2O5 , O5 is written as _______.
    15·1 answer
  • Determine the value of the equilibrium constant, Kgoal, for the reaction
    10·1 answer
  • Define density. Plz help me
    6·1 answer
  • Milk (pH 6.7)
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!