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WARRIOR [948]
2 years ago
8

Given the reaction: A + B <--> C + D

Chemistry
1 answer:
Lady_Fox [76]2 years ago
6 0

Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }                                       <----- Equilibrium expression

K = \frac{[2 M] [2 M]}{[1 M] [1 M] }                                     <----- Insert molarities

K = \frac{4}{1  }                                                <----- Multiply

K = 4                                                <----- Divide

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3 years ago
(A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered
FrozenT [24]

Answer:

1) 0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

2) The mass % calcium carbonate in the tablet is 50.58%.

3) The mass % of calcium in calcium carbonate  is 40.00 %.

4) Mass of calcium in a tablet is 0.33 g.

Explanation:

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Mass of the watch glass = 46.719 g

Mass of the watch glass + mass of calcium carbonate = 47.544 g.

Mass of calcium carbonate = 47.544 g - 46.719 g = 0.825 g

0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

Mass of calcium carbonate = 0.825 g

Percentage of calcium in tablet:

\%=\frac{\text{Mass of calcium carbonate }}{\text{Mass of tablet}}\times 100

\%=\frac{0.825 g}{1.631 g}\times 100=50.58\%

The mass % calcium carbonate in the tablet is 50.58%.

Percentage of calcium in calcium carbonate :

Molar mass of calcium carbonate = 100 g/mol

Atomic mass of calcium = 40 g/mol

Percentage of calcium in calcium carbonate :

\%=\frac{\text{atomic mass of calcium}}{\text{Molar mass of}CaCO_3}\times 100

\%=\frac{40 g/mol}{100 g/mol}\times 100=40.00\%

The mass % of calcium in calcium carbonate  is 40.00 %.

Mass of calcium carbonate = 0.825 g

The mass % of calcium in calcium carbonate  is 40.00 %.

Mass of calcium in a tablet : x

40.00\%=\frac{\text{Mass of calcium in a tablet}}{0.825 g}\times 100

x=40.00\times \frac{0.825 g}{100}=0.33 g

Mass of calcium in a tablet is 0.33 g.

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3 years ago
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