From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.
Na2CO3 = 2Na+ + CO3^2-
7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
Answer:
20cm³ of sulphuric acid reacts completely with excess zinc to form 0.1 mole of hydrogen gas. Calculate the molarity of the acid used.?
Molarity= mol/volume
Molarity= 0.1/20
Molarity= 0.005mol/L
Explanation:
Explanation:
All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons.
Love the toradora pfp, also the answer to your question is...
answer: from newtons second law of motion,
F=ma hence,
F=20N
m=5kg so,
20=5×a
a=4m/s^2
The answer is: [B]: "covalent bond" .
_________________________________________________
