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creativ13 [48]
3 years ago
11

5)

Chemistry
1 answer:
zmey [24]3 years ago
6 0

Answer:

Option B. 450mL

Explanation:

To obtain the volume of water that must be added, we need to First find the volume of the diluted solution.

C1 (concentration of the stock solution) = 8M

V1 (volume of the stock solution) = 150mL

C2 (concentration of the diluted solution) = 2M

V2 (volume of the diluted solution) =?

Using the dilution formula C1V1 = C2V2, we can obtain the volume of the diluted solution as follow:

C1V1 = C2V2

8 x 150 = 2 x V2

Divide both side by 2

V2 = (8 x 150)/2

V2 = 600mL

The volume of water added is simply the difference between the volume of the diluted solution and that of the stock solution. This is illustrated below

Volume of water added = V2 - V1 = 600 - 150 = 450mL

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den301095 [7]

Answer:

9.  8.2x10¹⁴ Hz

Explanation:

Wavelength λ = 366 nm

Formula: Frequency = C / λ

To find the wavelength in m,

1 nm = 1.0x10⁻⁹ m

So, 366 nm = ?

= 3.66x10⁻⁷ m

Frequency = 3.0x10⁸m.s-1 / 3.66x10⁻⁷ m

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8 0
3 years ago
A cool, yellow-orange flame is used to heat the crucible. Would this affect the mass of the crucible? If so, how?
s2008m [1.1K]

Answer:

yes

Explanation:

Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.

5 0
3 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
3 years ago
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8 0
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Explanation:

7 0
3 years ago
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