Answer:
Oxidation half-reaction : Na(s) → Na⁺ + 1 e-
Reduction half-reaction: Cl₂ + 2 e- → 2 Cl⁻
Explanation:
Oxidation half-reaction: solid sodium (Na(s)) has an oxidation number of 0. It loses 1 electron and forms the cation Na⁺. So, the half-reaction is the following:
Na(s) → Na⁺ + 1 e-
Reduction half-reaction: chlorine gas (Cl₂) has an oxidation number of 0. Each atom of Cl gains 1 electron to form two Cl⁻ ions, according to the following half-reaction:
Cl₂ + 2 e- → 2 Cl⁻
The total oxidation-reduction reaction is obtained by adding the oxidation half-reaction multiplied by 2 (to balance the electrons) and the reduction half-reaction, as follows:
2 x (Na(s) → Na⁺ + 1 e-)
Cl₂ + 2 e- → 2 Cl⁻
--------------------------------
2Na(s) + Cl₂ → 2NaCl
Answer : The conditional formation constant is
Explanation :
First we have to calculate the formation constant.
As we are given that:
Thus, the formation constant is
Now we have to calculate the conditional formation constant.
The expression used as:
where,
= conditional formation constant = ?
= activity coefficient at pH 9.00 = 0.041
= formation constant =
Now put all the given values in the above expression, we get:
Therefore, the conditional formation constant is
The speed of sound depends upon
a) air density
b) temperature
c) pressure
d) humidity
so there can be different reasons that the instrument goes out of tune outside.
However in the given options the best is The speed of sound decreases with a decrease in temperature.
Answer:
<u><em>80 micro henry</em></u>
Explanation:
the inductance of inductors connected in series is calculated by L= L₁+L₂+L₃+L₄= 20+20+20+20= 80 micro henry