Answer:
Option B. 450mL
Explanation:
To obtain the volume of water that must be added, we need to First find the volume of the diluted solution.
C1 (concentration of the stock solution) = 8M
V1 (volume of the stock solution) = 150mL
C2 (concentration of the diluted solution) = 2M
V2 (volume of the diluted solution) =?
Using the dilution formula C1V1 = C2V2, we can obtain the volume of the diluted solution as follow:
C1V1 = C2V2
8 x 150 = 2 x V2
Divide both side by 2
V2 = (8 x 150)/2
V2 = 600mL
The volume of water added is simply the difference between the volume of the diluted solution and that of the stock solution. This is illustrated below
Volume of water added = V2 - V1 = 600 - 150 = 450mL
