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Dmitry_Shevchenko [17]
3 years ago
13

Simplify square root of five times the quantity ten minus four square root of two. 14 fifteen square root of two five square roo

t of two end root minus four square root of ten ten square root of five end root minus four square root of ten
Mathematics
2 answers:
Vinvika [58]3 years ago
3 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

√5 x (10 - 4√2)

Multiply the value outside the bracket by everything inside:

10√5 - 4√10

Thus, your answer is ten square root of five minus four square root of 10

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

Rainbow [258]3 years ago
3 0

Answer:

\sqrt{2}

Step-by-step explanation:

The given expression is

\sqrt{5 \times 10} -4\sqrt{2}

First, we solve the product

\sqrt{50} -4\sqrt{2}

Then, separate number 50 in two factor

\sqrt{2 \times 25}- 4\sqrt{2}

But, we know that \sqrt{25}=5, so

5\sqrt{2} -4\sqrt{2}

Now, we group whole numbers, and solve

(5-4)\sqrt{2}=\sqrt{2}

Therefore, the given expression is equal to \sqrt{2}

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the width of a rectangle is 8 feet and the diagnal length of the rectangle is 13 feet which measurement is closest to the length
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Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself

Step-by-step explanation:

Okay so you have a weigh of 8 and a diagonal of 13.

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Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.

In this case I’m substituting a for 8.

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√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.

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If T is the midpoint of segment RS then, Segment RT is congruent to segment TS..<br> Help please!!!!
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