<span><span><span><span><span>(5)</span><span>(<span>−3</span>)</span></span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span><span>=<span><span><span><span>−15</span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span><span>−15</span>−<span>(<span>−12</span>)</span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span>−3</span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span>(<span>−9</span>)</span></span></span><span>=<span>3</span></span>
I'm assuming that you meant:
y = 7x² + 3
Remember! Inputs are always x values (unless stated otherwise). Meaning the problem says:
x = 4
y = 7(4)² + 3
The square only applies to the 4. The 7 is not going to be squared! (To be exact it only applies to whatever the value of x is.
4² = 4·4 = 16
Remember:
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Follow PEMDAS from left to right (or in the case above from top to bottom).
7·16 + 3 = ?
16·7 = 10·7 + 6·7 = 70 + 42 = 112
(All I did to multiply was break it up into parts. If it confuses you don't worry about it, and just multiply it out like normal or use a calculator if you are allowed to)
112 + 3 = ?
Our output is:
115!
Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is
The standard deviation of the random sample is
Therefore, The mean is 2.5 and the standard deviation is 1.08.
Answer:
7
Step-by-step explanation:
