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Dafna1 [17]
3 years ago
5

Evaluate f(x) = -2x squared - 4 for x = 3

Mathematics
1 answer:
damaskus [11]3 years ago
7 0
f(x)=-2x^2-4;\ \text{for}\ x=3\\\\\text{substitute:}\\\\f(3)=-2\cdot3^2-4=-2\cdot9-4=-18-4=-22
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Which expression below are equivalent to 2(2x + 1)
emmainna [20.7K]

Answer:

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Step-by-step explanation:

you are doing distributive property so the answer could possibly be: 4x+2

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3 years ago
Please answer this correctly
cluponka [151]

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2:30pm

Step-by-step explanation:

7 0
3 years ago
the width of a rectangle is 4 inches less than the length ,the perimeter is 48,what is the dimensions?
zalisa [80]
Answer: 10 inches × 14 inches

Work:

length = x inches
width = x - 4 inches
perimeter = 2(l+w)

48 = 2[(x)+(x - 4)]
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3 0
3 years ago
Read 2 more answers
CALC BC HELPPP!!!??? 100PTS!!!
lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}

8 0
2 years ago
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AURORKA [14]

Answer:

Reflection across the x-axis: (-4,2)

Reflection across the y-axis: (4,-2)

Step-by-step explanation:

Going based off of what I see, a reflection across the x axis changes "y" & the same rule applies to the y axis.

It should be an L shape.

7 0
3 years ago
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