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ipn [44]
3 years ago
6

What is the area of a circle whose equation is (x-3)² + (y + 1) ² =81?

Mathematics
1 answer:
kupik [55]3 years ago
4 0
Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle: 

\frac{(x-x_{1})^2}{r^2}+ \frac{(y-y_{1})_^2}{r^2}=1

Where (x_{1}, y_{1}) is the centre of the circle. In this case, we don't need to know the centre. Just the radius. 

Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81. 

\frac{(x-3)^2}{81}+ \frac{(y+1)^2}{81}=1

Great! We now know the radius of the circle. It is \sqrt{81} because it is the bottom fraction. Now we know that the radius is 9. 

So now lets input this into the area of circle formula: 

A=πr^2 

Now we insert our radius. 

A=9^2π 

=A=81π 

You can convert that into a decimal if you wish. 

Hope this helped!

~Cam943, Moderator
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Solve system of equations:<br> 4l + 8m = 40<br> 5l + 2m = 28<br> Please show steps!
ziro4ka [17]
Answer:

l = 9/2 or 4.5

m = 11/4 or 2.75

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4l + 8m = 40

8m = 40 - 4I

m = 5 - 0.5l

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5l + 2(5 - 0.5l) = 28

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8m + 18 = 40

8m = 22

m = 22/8

m = 2.75

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3 years ago
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