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3 years ago

an object accelerates from rest to a velocity of 4.om / s over a distance of 20m . what was it's acceleration

1 answer:

7 0

Acceleration is the change in velocity over time. There's are formula's for such problems which are called kinematics equations. Look em up. One of them doesn't have t (time) in them you would normally use that one to solve this problem. 16/2/20=a=0.4m/s^2

I did it for you but please look it up, understand and memorize it ;)

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3 years ago

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2 years ago

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d1i1m1o1n [39]

Answer:

8 / 15

Step-by-step explanation:

By Pythagoras theorem,

OP² + PQ² = OQ²

OP² + 8² = 17²

OP² = 17² - 8²

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OP² = 225

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OP = 15

Formula : -

Tan θ = Opposite side / Adjacent side

Here,

θ = Q

Opposite side = PQ = 8

Adjacent side = OP = 15

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3 years ago

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vova2212 [387]

Answer:

Step-by-step explanation:

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2 years ago

In a right triangle, one leg is 20 cm and the hypotenuse is 30 cm. To the nearest hundredth of a cm, find the length of the miss

max2010maxim [7]

Answer:

Step-by-step explanation:

Use Pythagoras’ theorem

square of hypotenuse = sum of squares of two other sides

let the missing side be d

30^2 = 20^2 + d^2

600 = 400 + d^2

d^2 = 200

d = square root of 200

d = 14.142 cm

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3 years ago

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