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boyakko [2]
3 years ago
10

an object accelerates from rest to a velocity of 4.om / s over a distance of 20m . what was it's acceleration

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0
Acceleration is the change in velocity over time. There's are formula's for such problems which are called kinematics equations. Look em up. One of them doesn't have t (time) in them you would normally use that one to solve this problem. 16/2/20=a=0.4m/s^2

I did it for you but please look it up, understand and memorize it ;) 
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Write 83 as a sum of tens and ones
Hoochie [10]
Well,

We can see that there are 8 10's and 3 1's.  So we can write 8 10's followed by 3 1's and join them with addition symbols.

83 = 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 1 + 1 + 1
6 0
3 years ago
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Solve the system of equations by graphing on your own paper. What is the y
xenn [34]

Answer: The coordinate of the solution is (0.25,-0.5)

Step-by-step explanation:

the solution is (0.25,-0.5) because when you graph them on a graph, they both intercept at that point.

3 0
2 years ago
Simply the expression given below (3x^3+4x^2+4x-12)+(-5x^3+9x^2-9x+20)
Svet_ta [14]

Answer:

1. Simplify: (4x2 - 2x) - (-5x2 - 8x).

Solution:

(4x2 - 2x) - (-5x2 - 8x)

= 4x2 - 2x + 5x2 + 8x.

= 4x2 + 5x2 - 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

Answer: 3x(3x + 2)

Step-by-step explanation:

6 0
2 years ago
PPPPPPLLLLLLEEAAASSEE HELLLPPP WIL MARK BRAINLIEST the brackets for a shelf are in the shape of a triangle. Find the angles of t
ahrayia [7]

Answer:

Step-by-step explanation:

Sum of the angles of a triangle is ALWAYS 180°.

2x+3x+5x = 180°

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x = 18°

2x = 36°

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6 0
2 years ago
Is the answer a, b, c, or d.
ale4655 [162]
The correct answer is d.

We have the following system of linear equations:

(I) 4x+7y=-14
(II) 8x+5y=8

Let's use the elimination method, then let's multiply the equation (1) \times(-2) and subtracting (I) and (II):

(I) -2(4x+7y)=-2(-14)
∴ -8x-14y=28

(I) -8x-14y=28
(II) 8x+5y=8
____________________
(III)  -9y=36

∴  y=-4

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

4x+7(-4)=-14
∴ 4x-28=-14
∴ 4x=14
∴ x=\frac{14}{4}
∴ \boxed{x=\frac{7}{2}}

Let's substitute the values of x and y into (I) and (2)

(I) 4(\frac{7}{2})+7(-4)=14-28=-14
(II) 8(\frac{7}{2})+5(-4)=28-20=8

Finally the answer is:

\boxed{x=\frac{7}{2} \rightarrow x= 3 \frac{1}{2}}

4 0
2 years ago
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