Depending on the first term, the sequences
would work.
If the sequence began at 6,
If the sequence began at 1,
If the sequence began at 3,
Answer:
<em>f( g ( - 2 ) ) = - 14 </em>
Step-by-step explanation:
f(x) = - 2x + 4
g(x) = 3x² - x - 5
f( g ( - 2 ) ) = ?
g( - 2 ) = 3( - 2 )² - ( - 2 ) - 5 = 12 + 2 - 5 = 9
f(9) = - 2 × 9 + 4 = - 14
<em>f( g ( - 2 ) ) = - 14</em>
Answer:
Step-by-step explanation:
(x−a)(x−b)=x2−(a+b)x+ab
Now, this with the third bracket.
(x2−(a+b)x+ab)(x−c)=x3−(a+b+c)x2+(ac+bc+ab)x−abc
But there’s another way to do this, which is easier. Assume the given expression is equal to 0, then, we can form a cubic equation as
x3−(sum−of−roots)x2+(product−of−roots−taken−two−at−a−time)x−(product−of−roots) , which is essentially what we got above.
When a number is 3 times a first number. A third number is 100 more than the first number and the sum of the three numbers is 450, the numbers are 70, 170 and 210.
<h3>How to calculate the numbers?</h3>
Let the first number = x
Second number = 3x
Third number = x + 100
Sum = 450
The numbers will be:
x + 3x + x + 100 = 450
5x + 100 = 450
5x = 450 - 100
5x = 350
Divide
x = 350 / 5
x = 70
First number = 70
Second number = 3x = 3 × 70 = 210
Third number = x + 100 = 70 + 100 = 170
Therefore, the numbers are 70, 170 and 210.
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One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 450 , find the numbers.
