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4 years ago

Rewrite the following polynomial in standard form. 1 -9 + - X -X – 7x4 + x2 – 25 8

Mathematics

1 answer:

Naddika [18.5K]4 years ago

6 0

Answer:

-7x^4+x^2-x-33

Step-by-step explanation:

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The equation 2x^2+12x=4 is written in the form of 2(x-p)^2+q=0. what is the value of q?

hram777 [196]

1) Factor out the coefficient 2: 2x^2+12x=4 => 2(x^2 + 6x) = 4

2) Complete the square of x^2 + 6x: x^2 + 6x + 9 - 9. Then:

2(x^2 + 6x + 9 - 9) = 4

3) Rewrite the square as the square of a binomial:

2( [x+3]^2 - 9) = 4, or

2([x+3]^2) = 22, or

2( [x+3]^2 ) - 22 = 0

The value of q is -22.

7 0

3 years ago

-2(v - 2) = -3 – 2v

liq [111]

Answer:

no solution

Step-by-step explanation:

Given

- 2(v - 2) = - 3 - 2v ← distribute left side

- 2v + 4 = - 3 - 2v ( subtract 4 from both sides )

- 2v = - 7 - 2v ( add 2v to both sides )

0 = - 7 ← not possible

This indicates the equation has no solution

3 0

3 years ago

I really need help:)))

vovikov84 [41]

Answer:

0.985

Step-by-step explanation:

You can do 1 - 0.015 to solve this problem.

1 - 0.015 = 0.985

Hope that helps!

7 0

3 years ago

Read 2 more answers

surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo

balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

Tan(58°)*100m = h1 = 160m.

The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be:

h2 - h1 = 196.3m - 160m = 36.3m

6 0

3 years ago

Solve the linear system of equations using addition. Graph the equations to verify your solution. required.

zhenek [66]

<h3>Answer:</h3>

infinite solutions

<h3>Step-by-step explanation:</h3>

Add the two equations.

... (-4x) + (y) = (y +3) +(-4x -3)

Add 4x -y to both sides.

... -4x +y +4x -y = -4x +y +4x -y

... 0 = 0 . . . . . true for all values of x (or y)

Both equations describe the same line.

_____

The graph shows the first equation as a red line. The second equation is shown using a "blue dot" texture, so you can see it overlays the red line.

8 0

3 years ago