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raketka [301]
3 years ago
5

ABC and ADC are triangles. The area of triangle ADC is 52m^2

Mathematics
1 answer:
sweet [91]3 years ago
4 0

Given that,

ABC and ADC are triangles.

The area of ΔADC is 52 m².

Suppose , AD is the median.

According to figure,

We need to find the area of ΔABC

Using theorem of triangle

\bigtriangleup ADB +\bigtriangleup ADC=\bigtriangleup ABC

Here, Δ ADB = Δ ADC

So, 2 \bigtriangleup ADC=\bigtriangleup ABC

Put the value of Δ ADC

\bigtriangleup ABC =2\times52

\bigtriangleup ABC = 104\ m^2

Hence, The area of ΔABC is 104 m².

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lbvjy [14]

Answer:The equation wth x in the information can be written as

1/2 x = 38.5 , Upon solving, the number = 77

Step-by-step explanation:

Let the number Sara was thinking about be x

halving the number to get an answer = 38.5 can be expressed as

 1/2 X = 38.5

The equation with x in the information can be written as

1/2 x = 38.5

solving it becomes

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x = 38.5 x 2

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The number Sara was thinking about = 77

4 0
3 years ago
PLEASE HELP ASAP THIS IS THE LAST QUESTION AND I AM STUCK!!
Varvara68 [4.7K]
<h3>Answer:  B) 7 units</h3>

===========================================================

Explanation:

The y coordinates of the two points are the same, so we can subtract the x coordinates and apply absolute value

|R - T| = |-6 - 1| = |-7| = 7

Or we can say

|T - R| = |1 - (-6)| = |1 + 6| = |7| = 7

Either way, the two points are 7 units apart.

You could use the distance formula to get the same answer, but that's definitely overkill in my opinion. The trick mentioned above also could work if the x coordinates were the same, but the y coordinates were different. In any other case, you would have to use the distance formula.

5 0
3 years ago
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Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

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Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

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BigorU [14]

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Step-by-step explanation:

4 times 1 3/4 is 7

6 0
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