Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
The answer will be 40. As it doubles twice during 220mins- 10 to 20 and then 20 to 40.
X² = 17
To simplify this, you need to find the square root of x², which is x, and the square root of 17.
x = √17
Also remember that when you are using square root, the answer can be either positive or negative.
x = +/-√17 ≈ +/- 4.12
6 plus 6 is 12 then 12 plus 3 is 15 then 15 plus 3 and 3 is 21 then we do 21 plus 4.2 is 25.4 plus 3 is 28.4 hope this helps
