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tigry1 [53]
1 year ago
13

If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain

Mathematics
1 answer:
evablogger [386]1 year ago
3 0
\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}

the denominator cannot be zero, because the division by zero is not defined, therefore:

\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

Therefore the domain of (f o g)(x) is:

D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)

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Two sides of a triangle measure
Umnica [9.8K]

Answer:

A.

Step-by-step explanation:

4 + 8 = 12 which is < 13.

3 0
3 years ago
A boat traveled 150 miles downstream (with the current) and back (against the current). The trip downstream took 10 hours. The t
Margarita [4]

Answer:

b= 10 miles/hr and c= 5 miles/hr

Step-by-step explanation:

Let it's downstream and upstream speed be d and u respectively

also speed of the boat be b and speed of stream be c.

as per question d = 150/10= 15 miles/hr

and, u= 150/30= 5 miles/hr

also we know d= b+c = 15.....i and u = b-c= 5....ii

solving i and ii we get b= 10 miles/hr and c= 5 miles/hr

3 0
2 years ago
F(x + 1) = 3x - 7<br> f(x) = ?<br> Cevabi kitabda=3x-10<br> Nasil yapmiş kitabda
lina2011 [118]

Answer:

<h2>f(x) = 3x + 4</h2>

Step-by-step explanation:

f(x + 1) = 3x - 7

f(x) = f(x + 1 - 1) = 3(x - 1) + 7 = 3x - 3 + 7 = 3x + 4

Check

f(x) = 3x + 4

f(x + 1) = 3(x + 1) + 4 = 3x + 3 + 4 = 3x + 7 CORRECT

8 0
3 years ago
Please solve this question <br>the answer is 45 degree ​
malfutka [58]

Answer:

∠ABC= 45°

Step-by-step explanation:

∠ABC= ∠BCD (alt. ∠s, AB//CD)

(2x +15)°= (3x)°

2x +15= 3x

3x-2x= 15 <em>(</em><em>-2x </em><em>on </em><em>both </em><em>sides)</em>

x= 15

Substituting the value of x:

∠ABC

= ∠BCD

= [3(15)]°

= 45°

7 0
2 years ago
Find the Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in
Zielflug [23.3K]

Answer:

Σ(-1)^kx^k for k = 0 to n

Step-by-step explanation:

The nth Maclaurin polynomials for f to be

Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......

The given function is.

f(x) = 1/(1+x)

Differentiate four times with respect to x

f(x) = 1/(1+x)

f'(x) = -1/(1+x)²

f''(x) = 2/(1+x)³

f'''(x) = -6/(1+x)⁴

f''''(x) = 24/(1+x)^5

To calculate with a coefficient of 1

f(0) = 1

f'(0) = -1

f''(0) = 2

f'''(0) = -6

f''''(0) = 24

Findinf Pn(x) for n = 0 to 4.

Po(x) = 1

P1(x) = 1 - x

P2(x) = 1 - x + x²

P3(x) = 1 - x+ x² - x³

P4(x) = 1 - x+ x² - x³+ x⁴

Hence, the nth Maclaurin polynomials is

1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n

= Σ(-1)^kx^k for k = 0 to n

6 0
3 years ago
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