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tekilochka [14]
3 years ago
9

Multiply. 32√⋅28√⋅3√⋅6√ Enter your answer, in simplest radical form, in the box.

Mathematics
1 answer:
valkas [14]3 years ago
4 0

Answer:

  48√7

Step-by-step explanation:

  \sqrt{32}\cdot\sqrt{28}\cdot\sqrt{3}\cdot\sqrt{6}=\sqrt{(2^5)(2^2\cdot 7)(3)(2\cdot 3)}\\\\=\sqrt{(2^4\cdot3)^2(7)}=2^4\cdot 3\sqrt{7}=\boxed{48\sqrt{7}}

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The sum of the first ten terms of a linear sequence is 145. the sum of the next ten term is 445. find the sum of the first four
chubhunter [2.5K]

The sum of the first four terms of the sequence is 22.

In this question,

The formula of sum of linear sequence is

S_n =\frac{n}{2}(2a+(n-1)d)

The sum of the first ten terms of a linear sequence is 145

⇒ S_{10} =\frac{10}{2}(2a+(10-1)d)

⇒ 145 = 5 (2a+9d)

⇒ \frac{145}{5} =2a+9d

⇒ 29 = 2a + 9d  ------- (1)

The sum of the next ten term is 445, so the sum of first twenty terms is

⇒ 145 + 445

⇒ S_{20} =\frac{20}{2}(2a+(20-1)d)

⇒ 590 = 10 (2a + 19d)

⇒ \frac{590}{10}=2a+19d

⇒ 59 = 2a + 19d -------- (2)

Now subtract (2) from (1),

⇒ 30 = 10d

⇒ d = \frac{30}{10}

⇒ d = 3

Substitute d in (1), we get

⇒ 29 = 2a + 9(3)

⇒ 29 = 2a + 27

⇒ 29 - 27 = 2a

⇒ 2 = 2a

⇒ a = \frac{2}{2}

⇒ a = 1

Thus, sum of first four terms is

⇒ S_4 =\frac{4}{2}(2(1)+(4-1)(3))

⇒ S_4 =2(2+(3)(3))

⇒ S₄ = 2(2+9)

⇒ S₄ = 2(11)

⇒ S₄ = 22.

Hence we can conclude that the sum of the first four terms of the sequence is 22.

Learn more about sum of sequence of n terms here

brainly.com/question/20385181

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You could buy 13 bananas.
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Sladkaya [172]

Answer:

See attachment

Step-by-step explanation:

Isolate y in the first inequality:

2x + 4y < -16\\4y < - 16 -2 x\\y < -4 -\frac{1}{2} x\\y < -\frac{x+8}{2} \\

Now, with both x and y inequalities found, graph it.

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2 years ago
If the discriminant is less than zero than the equation has ______________ solutions.
aleksley [76]

Answer:

The discriminant is the part under the square root in the quadratic formula, b²-4ac. If it is more than 0, the equation has two real solutions. If it's less than 0, there are no solutions. If it's equal to 0, there is one solution.

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Step-by-step explanation:

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