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3 years ago

Someonnnne helllppppp !!!

Mathematics

1 answer:

WARRIOR [948]3 years ago

6 0

First, remove the parentheses:

7x+7=1

Then, subtract 7 from both sides of the problem.

7x-6

Then, divide 7 from 7x, and divide 7 to -6.

x= -6/7 or -0.85

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Ms Happy has decided to start wearing a face mask, because it is now required of her to do so. The mask she has started wearing

Alchen [17]

Answer:

37.20 %

Step-by-step explanation:

Circumference = 2 × pi × r

30 = 2 × 3.14 × r

r = 4.7770700637

Area of her face = pi × r²

3.14 × 4.7770700637²

= 71.6560509556 in²

Area of the mask = 9 × 5 = 45 in²

Uncovered area

= 71.6560509556 - 45

= 26.6560509556 units²

% of uncovered area:

26.6560509556/71.6560509556 × 100

37.2%

6 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

Someone plz help me giving brainliest

sukhopar [10]

Answer:

1/14

Step-by-step explanation:

1 - 5/7 = 7/7 - 5/7 = (7-5)/7

Subtract. 7 - 5 = 2

= 2/7

Now we have to multiply 2/7 and 1/4

We get 2/7 x 1/4 = 1/14

7 0

3 years ago

The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.

GenaCL600 [577]

In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.

In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.

Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.

8 0

3 years ago

Read 2 more answers

Which of the following ratios are equivalent to 6:9? Choose all that apply

kipiarov [429]

Answer:

Dear we can't give you an answer without the options.

Step-by-step explanation:

ratios that are equivalent to 6:9 are however

2:3, 6:9, 12:18, 18:27, 24:36, 30:45 I believe.

5 0

3 years ago