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Ainat [17]
3 years ago
14

Mario ordered a pizza for dinner when it arrived Mario quickly ate 1/8 of the pizza or Mario's getting napkins his pet poodle at

e 1/3 of the pizza B. Write a numerical expression to show the fraction of the pizza that's left

Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0
Sent a picture of the solution to the problem (s).

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I tried answering this but I don't think its right ​
iogann1982 [59]
Yeah that is correct. 3/4 is equal to .75
7 0
3 years ago
Read 2 more answers
The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?
AleksAgata [21]

Answer:

\large \boxed{2}

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}

Check:

\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}

It checks.

7 0
3 years ago
[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6
viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

              (b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

                  Height (in inches) of a 25 year old man is a normal random variable with mean g=71 and variance o^{2} =6.25.

To find:  (a) What percentage of 25 year old men are 6 feet, 2 inches tall

               (b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X>74in]

                           P[X>74] = P[\frac{X-g}{o} > \frac{74-71}{2.5}]

                                         = P[Z > 1.2]

                                         = 1 - P[Z ≤ 1.2]

                                         = 1 - Ф (1.2)

                                         = 1 - 0.8849

                                         = 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, 6ft 5in - X, 6ft]

     P[X > 6ft 5in I X > 6ft] = P[X > 77 I X > 72]

                                          = \frac{P[X > 77]}{P[ X > 72]}

                                          = \frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}]  }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }

                                          = \frac{P[Z >2.4]}{P[Z>0.4]}

                                          =  \frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }

                                          = \frac{1-0.9918}{1-0.6554}

                                          = \frac{0.0082}{0.3446}

                                          = 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0
3 years ago
Need help combining like terms!! PLS
sesenic [268]

Answer:

1 - 9/7n

Explanation:

1/7 - 3(3/7n - 2/7)

<em>distribute</em><em> </em><em>the</em><em> </em><em>3</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>2</em><em> </em><em>fractions</em><em> </em><em>inside</em><em> </em><em>the</em><em> </em><em>parenthesis</em>

1/7 - 9/7n + 6/7

<em>add</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em><em>(</em><em>1</em><em>/</em><em>7</em><em> </em><em>+</em><em> </em><em>6</em><em>/</em><em>7</em><em>)</em>

7/7 - 9/7n

<em>or</em>

1 - 9/7n

3 0
3 years ago
Read 2 more answers
What are the factors of 16
zimovet [89]

The factors of 16 is actually 1,2,4,8,16

Hope I helped you out! Enjoy! :)

4 0
3 years ago
Read 2 more answers
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