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hram777 [196]
3 years ago
5

Slope and rate of changes describe the same value true or false​

Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer:

True

Step-by-step explanation:

“Rate of change” means the same as “slope.” If you are asked to find the rate of change, use the slope formula or make a slope triangle.

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Solve for x in the equation 3 x squared minus 18 x + 5 = 47.
ryzh [129]

Answer:

x= 3 +\sqrt{23}, 3 -\sqrt{23}

Step-by-step explanation:

You use the quadratic formula to get x= \frac{18+6\sqrt{23} }{6} ,\frac{18-6\sqrt{23} }{6}

Then you simplify and get the answers x= 3 +\sqrt{23}, 3 -\sqrt{23}

​​  

​​  

6 0
3 years ago
Read 2 more answers
Answer for 14+3y < 65
ivanzaharov [21]
Hey there!

14 + 3y < 65

SOME people replace “<”, “>”, “≥”, or “≤” as an equal sign (=) to make it easier to solve

14 + 3y < 65
14 + 3y = 65

SUBTRACT by 14 on both of your sides
3y + 14 - 14 = 65 - 14
CANCEL out: 14 - 14 because that gives you 0
KEEP: 65 - 14 because it helps you solve for “y”

**65 - 14 = 51**

NEW EQUATION: 3y = 51

DIVIDE by 3 both of your sides
3y/3 = 51/3
CANCEL out: 3/3 because that gives you 1
KEEP: 51/3 because it gives you the value of “y”



NEW EQUATION: y = 51/3

**51/3 = 17**

Answer: y = 17 ☑️

☑️ OVERALL ANSWER FOR YOU: y < 17 ☑️
NOTE: it’s an OPEN circle SHADED to the LEFT

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0
3 years ago
Read 2 more answers
Bre works 12 hour shifts 3 days a week and makes $25.64 per hour. How much does Bre make in 1 week?
Alona [7]

Answer:

923.04 $

Step-by-step explanation:

1 hour: 25.64 $

36 hour: x

x=36×25.64

x=923.04$

8 0
3 years ago
Read 2 more answers
“a railroad bridge spans a gorge 40 feet wide and connects two cliffs at heights of 98 and 158 feet above the bottom of the gorg
VMariaS [17]

Answer:

Height above the bottom gorge is 113 feet

Step-by-step explanation:

The width of the gorge = 40 feet

The height of the higher cliff = 158 feet

The height of the lower cliff = 98 feet

The length of the bridge = √((158-98)² + 40²) = 72.11 feet

The slope of the bridge = (158-98)/40 = 1.5

The length of 1/4 of the bridge from the lower cliff =72.11 - 3/4×72.11 = 18.03 feet

The angle of inclination of the bridge = tan⁻¹(1.5) = 56.31°

The height above the bottom at 3/4 from the higher cliff = The height above the bottom at 1/4 from the lower cliff = 98+ 18.03×sin(56.31 ) = 113 feet

Which can also be found directly from the heights of the two cliffs knowing that 3/4 from the higher cliff = 1/4 from the lower cliff giving;

Height above the bottom gorge = 98 + 1/4×(158 - 98) = 113 feet.

8 0
3 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
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