I think its r=I+7 because that would be the equation
we know that
If V is the midpoint of SU
then
SV=VU
substitute the given values
2x+18=8x-6
solve for x
8x-2x=18+6
6x=24
<h2>x=4</h2>
Find SV
SV=2x+18
SV=2(4)+18
<h2>SV=26 units</h2>
so
<h2>VU=26 units</h2>
and
SU=2SV
SU=2(26)
<h2>SU=52 units</h2>
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:

Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
9514 1404 393
Answer:
A, M, N, F
Step-by-step explanation:
I find it easier to look at the graph, rather than mess with the coordinate transformations. Each image point is the same distance from the line of reflection that its pre-image point is. The line joining the two points is perpendicular to the line of reflection.
See attached for the reflected points.
__
The red and turquoise dashed lines are the lines y=x and y=-x, respectively. The same-colored arrows show the reflection of the relevant point.
_____
The transformations of interest are ...
(x, y) ⇒ (y, x) . . . . reflection over y = x
(x, y) ⇒ (-x, y) . . . . reflection over y-axis
(x, y) ⇒ (x, -y) . . . . reflection over x-axis
(x, y) ⇒ (-y, -x) . . . . reflection over y = -x
this is as far as i could get. sorry