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eimsori [14]
3 years ago
8

Simplify the square root of 61.

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0
Decimal form is 7.81
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Help! i need the answer to this question plsss NO LINKS AND NO DOING IT JUST FOR THE POINTS Will give brainliest to the first se
Alex_Xolod [135]

2745

Step-by-step explanation:

solve it like simultaneously

180x+120y greater than 5145

180x+120y greater than 2400

eliminate x

y will now be greater than 2745

5 0
3 years ago
Which ordered pair is the solution to the system of equations?
SOVA2 [1]
To find the solution, we use the substitution method. 

x+y=-1
<span>x-3y=11
</span>
x+y = -1-y
  -y       

x = -1-y

Now apply the value of x into the other equation.

x-3y=11
-1-y-3y = 11

Combine like terms

-4y -1 = 11
       +1    +1
-4y = 12

-4y = 12
-4y/-4 = 12/-4
y = -3

Now, apply the value of Y to one equation to find x.

y = -3

x -3 = -1
   +3   +3  
 
x= 2

Now we have the value for both, x and y.
x = 2
y =-3

Final answer: A. <span>(2, −3)</span>
3 0
3 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
The area of a regular hexagon inscribed in a circle with radius 2 is . Round your answer to the nearest tenth.
Verdich [7]

Answer:

10.4 to nearest tenth.

Step-by-step explanation:

If we draw lines from the centre of the circle to each vertex of the hexagon we get 6  equilateral triangles  of side length 2.

Altitude of each triangle  = sqrt(2^2 - 1^2)

= sqrt3.

So the area of 1 triangle = 1/2 * 2 * sqrt3

= sqrt3

Therefore the area of the hexagon = 6 * sqrt3

= 6sqrt3

= 10.3923

6 0
3 years ago
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan
torisob [31]

The point slope form of the line which passes through the points (-5,-1) and (10,-7) is \fbox{\begin\\\ \math 2x+5y=-15\\\end{minispace}} i.e., \fbox{\begin\\\ \bf option C\\\end{minispace}}.

Further explanation:

It is given that line passes through the points (-5,-1) and (10,-7).

The objective is to determine the point slope form of the line which passes through the points (-5,-1) and (10,-7).

The options given are as follows:

Option A: 2x-5y=-15

Option B: 2x-5y=-17

Option C: 2x+5y=-15

Option D: 2x+5y=-17

Consider the point (-5,-1) as (x_{1},y_{1}) and (10,-7) as (x_{2},y_{2}).

Slope of a curve is defined as the change in the value of y with respect to change in value of x.

The slope of the line is calculated as follows:

\fbox{\begin\\\ \math m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\end{minispace}}

To obtain the value of slope substitute the value of x_{1},y_{1},x_{2},y_{2} in the above equation.

\begin{aligned}m&=\dfrac{-7-(-1)}{10-(-5)}\\&=\dfrac{-6}{15}\\&=\dfrac{-2}{5}\end{aligned}

Therefore, the slope of the line is \fbox{\begin\\\ \math m=\dfrac{-2}{5}\\\end{minispace}}

The general way to express the equation of a line in its point slope form is as follows:

\fbox{\begin\\\ \math (y-y_{1})=m(x-x_{1})\\\end{minispace}}

To obtain the point slope form of the equation of the line substitute the value of m, x_{1} and y_{1} in the above equation.

\begin{aligned}(y-(-1))&=\dfrac{-2}{5}(x-(-5))\\(y+1)&=\dfrac{-2}{5}(x+5)\\5y+5&=-2x-10\\5y+2x&=-15\end{aligned}

From the above calculation it is concluded that the point slope form the equation of a line is \fbox{\begin\\\ \math 5y+2x=-15\\\end{minispace}}

Figure 1 (attached in the end) represents the graph of the function 5y+2x=-15.

This implies that the correct option for the point slope form of the line is option C.

Therefore, the point slope form of the line which passes through the points (-5,-1) and (10,-7) is 2x+5y=-15 i.e., option C.

Learn more:

1. A problem to complete the square of quadratic function brainly.com/question/12992613  

2. A problem to determine the slope intercept form of a line brainly.com/question/1473992

3. Inverse function brainly.com/question/1632445.

Answer details

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Equation, linear equation, slope, intercept, x-intercept, y-intercept, intersect, graph, curve, slope intercept form, line, y=3x/2-3, standard form, point slope form.  

6 0
3 years ago
Read 2 more answers
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