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seropon [69]
3 years ago
5

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

Mathematics
1 answer:
pashok25 [27]3 years ago
7 0

Answer:

Yes, it is true that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1.

Step-by-step explanation:

Let us try to factorize x^4+3x^3-2x^2-3x+1

x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3

Let us try to make a whole square of the given terms:

\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\

--------------

Formula used above:

a^{2} -2 \times a \times b +b^{2}  = (a-b)^2

In the above equation, we had a = x, b = 1.

--------------

Further solving the above equation, taking 3x common out of 3x^3-3x

\Rightarrow (x^2-1)^2+3x(x^2-1)\\

Taking (x^{2} -1) common out of the above term:

\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)

So, the two factors are (x^2-1)\ and\ (x^2+3x-1).

\therefore The statement that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1 is <em>True.</em>

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In order to determine the  cubic centimeter one container can hold, the volume of the container has to be determined.

Volume of the container = volume of the cylinder + (2 x volume of the hemisphere)

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To learn more about the volume of a hemisphere, please check: brainly.com/question/26840364

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