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Vitek1552 [10]
3 years ago
7

X-5 times 10 first will get brainliest!

Mathematics
2 answers:
Schach [20]3 years ago
4 0

Answer:

5x10=50

add the x-50

Step-by-step explanation:

Brainliest?

Evgen [1.6K]3 years ago
3 0

Answer:

x−50

Step-by-step explanation:

x−(5)(10)

=x+−50

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What values will complete this table to show direct variation? Help! And quick!!!
vlada-n [284]

Answer: 0 -4 and -8

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Eva payrolls for on a number cube and the number of cubes roll 24 times then what is a reasonable prediction for the number of s
Allushta [10]

Answer:

The reasonable prediction for successful rolls is 4.

Step-by-step explanation:

Assuming the rolling cube  is a fair 6 sided cube, so the probability of success of one roll is given as

P(Success)=\dfrac{Number\ of\ successful\ events}{Number\ of\ total\ events}

P(Success)=\dfrac{1}{6}

The total success is given as

P(Total\ Success)=P(Success)\times Number\ of\ events

For 24 rolls it is given as

P(Total\ Success)=P(Success)\times Number\ of\ events\\P(Total\ Success)=\dfrac{1}{6}\times 24\\P(Total\ Success)=4

So the reasonable prediction for successful rolls is 4.

3 0
3 years ago
Please help with this
Aleksandr-060686 [28]

Answer:

A

Step-by-step explanation:

(3x -14) + 9x is 90 degrees, so if you add 90 it becomes 180 degrees

It is 90 degrees because you can see that there is a right angle there

6 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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