The larger the negative number the smaller the value:
The order would be:
-4, -1/2, 1/4, 1/3, 1/2, 2/3, 2
Answer: Horizontal asymptote is 
and vertical asymptotes are 
Step-by-step explanation:
Since we have given that
We need to find the horizontal and vertical asymptotes.
Since vertical asymptotes will occur where the denominator becomes zero.
So, here denominator is 
Now,
And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.
Hence, horizontal asymptote is and vertical asymptotes are
The answer is 12π.
To get the volume of the cone, we need the height. The radius is given.
V = πr² × (h/3)
The total surface area of the cone is:
SA = πr² + πrl where r is radius and l is slant height
24π = π(3)² + π(3)(l)
24π = 9π + 3πl
24π - 9π = 3πl
15π = 3πl
l = 15π / 3π
l = 5
Using Phytagoras, we can calculate the height of the cone:
l² = h² + r²
5² = h² + 3²
25 - 9 = h²
h = √16
h = 4
Therefore the volume is:
V = π(3)² × (4 / 3)
V = 3π × 4
V = 12π
Answer:
Horizontal shift of 1 unit to the right, a vertical shift upward of 6 units, and a vertical stretch by a factor of 3 ..
Step-by-step explanation:
Given function is:
3[|x-1|+2]
Can also be written as:
3|x-1|+6
As we can see that the -1 is grouped with x which means it is a horizontal shift of 1 unit to the right.
Now, 6 is added to the function and it is not grouped with x which means that there is a vertical shift of 6 units upward.
Lastly, 3 is multiplied with the term containing x which means that there is a vertical stretch of 3 units.
Hence, the correct option is:
Horizontal shift of 1 unit to the right, a vertical shift upward of 6 units, and a vertical stretch by a factor of 3 ..
