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natka813 [3]
3 years ago
7

I need help finding the Function notation

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

  1.5, -8, 0, 2f, 2/3

Step-by-step explanation:

j(x) = 2x means the function name is j, and it is a function of the variable x. To evaluate the function, you put the given value everywhere you see x, and do the arithmetic.

  j(0.75) = 2(0.75) = 1.5

  j(-4) = 2(-4) = -8

  j(0) = 2(0) = 0

  j(f) = 2f

  j(1/3) = 2(1/3) = 2/3

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She will have to pay $2,700.

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She is going to earn 40% of it, so she still have to pay 60% of it. 

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3 years ago
BRAINLIEST AWARD NO.2
zzz [600]

Answer:

A whole number first term to render as fifth term a value larger than 10000, should be at least 121

Step-by-step explanation:

The formula is given as recursive since it involves the previous number of the sequence, and defined as:

a_n=a_{n-1}*3+6

we also know that the first term is 4

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a_1=4\\a_2=4*3+6=18\\a_3=18*3+6=60\\a_4=60*3+6=186\\a_5=186*3+6=564\\

So if we want to find the first term in the case that the fifth one is greater than 10,000 using this recursive formula, now we have to start backwards, and say that the fifth term is "> 10000" and what the fourth one is.

Notice that if you have this definition for the nth term, we can obtain from it, what the previous term is to find the general rule:

a_n=a_{n-1}*3+6\\a_n-6=a_{n-1}*3\\\frac{a_n-6}{3} = a_{n-1}\\a_{n-1}=\frac{a_n}{3} -2

So the rule is to subtract 6 from he term, and divide the subtraction by 3. Then working backwards:

a_5>10000\\\frac{a_5}{3} -2>\frac{10000}{3} -2\\a_4>=\frac{10000}{3} -2\\\frac{a_4}{3} -2>\frac{\frac{10000}{3}-2}{3}-2 =\frac{10000}{9}-\frac{8}{3} \\a_3>\frac{10000}{9}-\frac{8}{3} \\\frac{a_3}{3} -2>\frac{\frac{10000}{9}-\frac{8}{3} }{3} -2=\frac{10000}{27} -\frac{8}{9} -2=\frac{10000}{27} -\frac{26}{9}\\a_2=\frac{10000}{27} -\frac{26}{9}\\\frac{a_2}{3} -2>\frac{\frac{10000}{27} -\frac{26}{9}}{3} -2=\frac{10000}{81} -\frac{80}{27} \\a_1>\frac{10000}{81} -\frac{80}{27}\approx 120.49

therefore, the starting first term should be at least about 121 to give a fifth term larger than 10,000

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Answer:

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hope this helps
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