Mathematics Diagnostic Assessment

The graphs below have the same shape. Complete the equation of the red<br> graph.

inn [45]

Answer:

Step-by-step explanation:

F(x) = 2 - x²

3 0

2 years ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

c)

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

d)

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

<u>For Bus:</u>

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

<u>For motorcycle:</u>

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

2 years ago

Which is the graph of y = 5log(x+3)

Maurinko [17]

Answer:

We are given a equation as:

5log(x+3)=5

We are asked to find a graph that is used to solve the above equation.

We can write the given equation as:

we will divide both side of the equation by 5 to obtain:

log(x+3)=1

Now we have to determine which graph represents the function:

y=log(x+3)

since we know that when x=-2.

y=log(-2+3)=log(1)=0

Hence, the graph should pass through (-2,0).

Hence, the graph that satisfies this is attached to the answer.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

You fly in a helicopter for 20 minutes that goes at a speed of 240 km per hour.How far did you go?

CaHeK987 [17]

You would go 4800 km per hour

4 0

3 years ago

Read 2 more answers

Point G is rotated 90°. The coordinate of the pre-image point G was (7.5), and its image Gʻis at the coordinate (5, 7).

matrenka [14]

<h3>Answer:</h3><h3>The Direction of the rotation is counterclockwise around the origin.</h3>

Step-by-step explanation:

What was Given was that Point G is rotated 90°. The coordinate of the pre-image point G was (7, –5), and its image G’ is at the coordinate (5, 7).

What you need to find was : What is the direction of the rotation.

So coming to conclusions is we have given that Point G is rotated 90°.

The Pre-image of G = ( 7, -5).

Translated image G' = ( 5 ,7).

By the Rotation rule of 90° is : (-y, x) 90 degree rotation counterclockwise around the origin.

(y, -x) 90 degree rotation clockwise about the origin.

We can from G (7,-5) and G'( 5 ,7) it is rotation counterclockwise around the origin.

Therefore, Direction of rotation is counterclockwise around the origin.

6 0

2 years ago