Answer:
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Step-by-step explanation:
what is this my guy
Answer:
There is a 95% confidence that the sample has a mean between 158.92 pounds and 171.48 pounds
Step-by-step explanation:
Given that mean (μ) = 165.2 pounds, standard deviation (σ) = 12.4 pounds, sample size (n) = 15 crates. Confidence (C) = 95% = 0.95
α = 1 - C = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
The z score of α/2 corresponds to the z score of 0.475 (0.5 - 0.025) which is 1.96. 
The margin of error (E) is given by:

The confidence interval = μ ± E = 165.2 ± 6.28 = (158.92, 171.48)
The confidence interval is between 158.92 pounds and 171.48 pounds. There is a 95% confidence that the sample has a mean between 158.92 pounds and 171.48 pounds
Answer:
32 one-dollar bills.
Step-by-step explanation:
Let <em>x </em>represent one-dollar bills and <em>y </em>represent two-dollar bills.
He has a total of 49 bills. Therefore:

The total amount of money James has is 66. <em>x</em> is worth one dollar, while <em>y</em> is worth two dollars. Therefore:

We have a system of equations. Solve by substitution:

Therefore, James has 32 one-dollar bills and 17 two-dollar bills.
Checking:

Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
5:4 is one ratio you can use for solving 5 being boys and 4 being girls
Step-by-step explanation: