What is the 7th term of 25,10,4,8/5

Mathematics

1 answer:

anyanavicka [17]3 years ago

5 0

This is a SpongeBob we are friends 25

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What is the answer to p=2L+2w ?

ollegr [7]

Perimeter (p) equals 2 times the length (L) plus 2 times the width (w).

This equation is used to find the perimeter of a rectangle.

7 0

3 years ago

Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

Ilya [14]

Answer:

$x^6+3x^3+3+\dfrac{1}{x^3}$

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

$(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}$

4 0

4 years ago

A student was solving the problem below. Look at their work and find the error.

rodikova [14]

The error is in line 3.

Specifically, the error is when the student went from $\sqrt{9}$ to simply $9$ without a square root over top. The $\sqrt{9}$ should simplify to 3.

Here's what the student should have done in terms of a step-by-step picture.

$\underline{\text{Line 1:}} \ \ \ 2\sqrt{45}-3\sqrt{5}\\\\\underline{\text{Line 2:}} \ \ \ 2\sqrt{9}*\sqrt{5}-3\sqrt{5}\\\\\underline{\text{Line 3:}} \ \ \ 2*3*\sqrt{5}-3\sqrt{5}\\\\\underline{\text{Line 4:}} \ \ \ 6\sqrt{5}-3\sqrt{5}\\\\\underline{\text{Line 5:}} \ \ \ 3\sqrt{5}\\\\$