Answer:
a.) -1 < x < 5
b.) x <= 1
Step-by-step explanation: Domain is the independent variable (x).
For both question a and b, make sure that the number under the square root does not end up being negative. And the denominator of the fractional number is not equal to zero when variable x is being substituted for any value.
a.) y = √ x + 1 /√ 25 − x^2
Domain : -1 < x < 5
That is the minimum value for x is 0 and the maximum value is 4
b. f(x) = (√ 1 − x ) ln x
Domain : x <= 1
That is, x is less than or equal to 1
The maximum value for x is 1. x can be
1, 0, -1, -2, -3, ..........
In general, √(y²) = |y|, since y can be positive or negative and y² would have the same value either way.
So,
1) if y > 0, then |y| = y, and
-15√(y²) = -15 |y| = -15y
2) if y < 0, then |y| = -y, and
-√(16y²) = -|4y| = -|4| |y| = -4 (-y) = 4y
Answer:
The answer is c
Step-by-step explanation:
Answer:
Step-by-step explanation:
So I'm looking at negative 64 and then four square to 16 and 16 times eight is 128 again May I'll show the steps you're subtracting off, you know, zero plus zero eso What we have is to native
