1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
malfutka [58]
2 years ago
9

An object is placed 21 cm from a concave lens of focal length 25 cm. what is the magnification?

Mathematics
1 answer:
wariber [46]2 years ago
6 0

The magnification is 0.54

Given,

The distance between object and concave lens, u = -21 cm

Focal length of the concave lens, f = -25 cm

Let m be the magnification.

m = v/u

Here v is the position of image.

We have to find v first.

By using lens equation we can determine v.

That is,

1/f = 1/v – 1/u

So,

- (1/25) = 1/v – (-1/21)

- (1/25) = 1/v + 1/21

1/v = - (1/25) – 1/21

1/v = (-25 – 21) / (21 x 25)

1/v = - (46/525)

Therefore v = - (525/46)

   v = -11.41 cm

Now we have to find magnification, m.

m = v/u

   = (-11.41) / (-21)

   = 0.54

Here magnification is 0.54

Learn more about concave lens here: brainly.com/question/12944945

#SPJ4

You might be interested in
Rapid Rental Car charges a $30 rental fee, $15 for gas, and $0.65 per mile driven. For the same car, Capital Cars charges $35 fo
andreev551 [17]

You gave me numbers but forgot the question. Without a question there is no answer.

5 0
3 years ago
A bag of gumballs contains 2 pink, 3 orange, 4 blue, 2 red, and 1 yellow
podryga [215]

Answer:

1/4

Step-by-step explanation:

there are 12 gumballs in total

1 yellow + 2 pink = 3 gumballs out of all 12

3 /12 is simplified to 1/4 as both numbers is divisible by 3

8 0
2 years ago
6. A regular pyramid has a square base. The perimeter of the base is 64 inches and the height of the pyramid is 12 inches. What
hichkok12 [17]

The volume is 1024. the base lengths are all 16 inches

4 0
3 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
Distance: Jack and Jill start from the same point and walk in'opposite directions. Jack
777dan777 [17]

Answer:

t = 6 km/hour

And, J would be 4 km per hour

Step-by-step explanation:

Let us assume the speed of Tom be T

And, the Speed of Jim  be J

Given that  

T - J = 2 km /hr ...........(i)

After 3 hours distance between them  = 30 km

As they are walking in the opposite direction

Thus,  

Net speed =T + J

L ÷ (T+J) = 3

30 ÷ (T+J) = 3

T +J =10 ..............(2)

After solving these two equations

2T = 12

t = 6 km/hour

And, J would be 4 km per hour

6 0
3 years ago
Other questions:
  • 95 POINTS REWARD!! VERY URGENT!!!!<br> Please answer the following questions correctly.
    10·2 answers
  • Find the difference.<br><br> (4x3−12x2−5)−(−8x2+4x+3)=
    15·2 answers
  • in a right triangle, the length of the hypotenuse is 20 inches and the length of one leg is 15 inches. What is the length of the
    13·2 answers
  • There are 35 more musicians in the String section of a city Symphony Orchestra than in its Brass section. There are 29 musicians
    13·1 answer
  • What are the points for y=-3x+4 and how do I graph it
    8·1 answer
  • Hypothesis: Family centered care is a significant predictor of children's health-related quality of life, independent of illness
    9·1 answer
  • What is the distance from (−4, 0) to (2, 5)? Round your answer to the nearest hundredth. (4 points) Group of answer choices 7.81
    7·2 answers
  • 8th grade math question need an answer asap
    6·2 answers
  • Pls help I’m not the best at math
    13·2 answers
  • 4. An oil palm plantation uses fertiliser at a rate of 350 kg per hectare. State the rate of
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!