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defon
3 years ago
9

What is 84 as a product of primes?

Mathematics
2 answers:
fomenos3 years ago
7 0
Answer: 3&7 are primes!
hichkok12 [17]3 years ago
7 0
3 and 7 are the primes ;)
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What are the values of x and y in the equation
vaieri [72.5K]

Answer:

The correct choice is D

Step-by-step explanation:

Value of X=20 and then to know the value of y we need to add

52+52= 104

360-104= 256

256÷2= 128

Y=128

5 0
2 years ago
Need help ASAP please​
victus00 [196]

Answer:

x = 5

Step-by-step explanation:

im too tired to explain just trust me

(5) + 2 = 7

2(5) + 3 = 13

13 * 7 = 91

4 0
2 years ago
Read 2 more answers
Can someone help me solve multiple step equations? For example (7t - 2) - (-3t + 1) = -3(1 - 3t)
artcher [175]

Answer:

t = 0

Step-by-step explanation:

(7t - 2) - (-3t + 1) = -3(1 - 3t)

because you can not do anything inside the parantheses, you distribute. there aren't any numbers on the left side of the parantheses on the left side of the equation so we just imagine the number 1. on the right side of the equation, just distribute normally

[ 1(7t - 2) -1(-3t + 1) = -3(1 - 3t) ]

will be

7t - 2 + 3t - 1 = -3 + 9t

add like terms

10t - 3 = -3 + 9t

subtract 9t from both sides

t - 3 = -3

add 3 to both sides

t = 0

3 0
3 years ago
Rewrite the quadratic function f(x) = (2x -3)(x+4) in standard form
jasenka [17]

Answer:

f(x) = 2x^2+5x-12

Step-by-step explanation:

5 0
3 years ago
What is the solution of the equation over the complex numbers
denis-greek [22]

<u>Answer:</u>

2i\sqrt{3}

-2i\sqrt{3}

<u>Step-by-step explanation:</u>

x^2 + 12

First set the equation to 0

x^2 + 12

x^2 + 12 = 0

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

x^2 + 12 = 0

x^2 + 12 + (-12) = 0 -12

x^2 = -12

Square root both sides of the equal sign.

x^2 = -12

\sqrt{x^2} = \sqrt{-12}

Take the square root on left sides of the equal sign.

\sqrt{x^2} = \sqrt{-12}

x = \sqrt{-12}

Take the square root on the right side of the equal sign. Remember \sqrt{-1} = i

x = \sqrt{-12}

x = \sqrt{4}*\sqrt{-1}\sqrt{3}}

x = 2i\sqrt{3}

<u>AND</u>

x = -2i\sqrt{3}

8 0
3 years ago
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