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70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ

Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) $m\angle EFQ=100\°$

2) $m\angle FEQ=66\°$

3) $m\angle EQF=14\°$

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle DFQ=\frac{1}{2}(arc\ QD)$

substitute the given value

$10\°=\frac{1}{2}(arc\ QD)$

$20\°=(arc\ QD)$

$arc\ QD=20\°$

step 2

Find the measure of arc FQ

we know that

$arc\ QD+arc\ FQ+arc\ EF=180\°$ ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

$20\°+arc\ FQ+28\°=180\°$

$arc\ FQ=180\°-48\°=132\°$

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)$

substitute the given value

$m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°$

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle FEQ=\frac{1}{2}(arc\ FQ)$

substitute the given value

$m\angle FEQ=\frac{1}{2}(132\°)=66\°$

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle EQF=\frac{1}{2}(arc\ EF)$

substitute the given value

$m\angle EQF=\frac{1}{2}(28\°)=14\°$

5 0

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What would you get if you add all odd numbers 1 through 7 inclusive

alexdok [17]

Well, it would be 1+3 which is 4. Then 4+5 which is 9. Then 9+7 which is 16 so your final answer would be 16

8 0

3 years ago

What is the value of r, the part of the job that Marina can complete in 1 hour? 0.1 0.4 0.5 0.6

kvv77 [185]

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4 0

3 years ago

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Find the two straight lines represented by x² + 5xy - 6y² = 0

Andreyy89

By factorizing, we have

$x^2 + 5xy - 6y^2 = (x - y) (x + 6y) = 0$