Volume=0.09m³
Density=4000kg/m³
Force=?
Density=mass/volume ⇒mass=volume×density
m=0.09×4000=360kg
Force=mass×accelaration
F=360×9.8
F=3528N
Answer:
3.46 s
Explanation:
First of all, we can calculate the acceleration of the elevator by using Newton's second law:
and the acceleration has the same direction of the net force (upward).
Now we can calculate the time takes for the elevator to cover a distance of S=15 m by using the following SUVAT equation:
where a is the acceleration and t the time. Re-arranging the equation, we find
Answer: 6.
All of the numbers in every row and column add up to 15! (Also, 6 is the only number not represented out of numbers 1 through 9.)
And to the representation to his problem you can clear,y see that 4.6 seconds is actully the the time of the whole parking. so if you just do a simple equation... 4.6x10p/2x15/10x2 would get your answer to 6
Answer:
depends of what kind of problem and you mean ALL
Explanation:
Answer:
Electric flux;
Φ = 30.095 × 10⁴ N.m²/C
Explanation:
We are given;
Charge on plate; q = 17 µC = 17 × 10^(-6) C
Area of the plates; A_p = 180 cm² = 180 × 10^(-4) m²
Angle between the normal of the area and electric field; θ = 4°
Radius;r = 3 cm = 3 × 10^(-2) m = 0.03 m
Permittivity of free space;ε_o = 8.85 × 10^(-12) C²/N.m²
The charge density on the plate is given by the formula;
σ = q/A_p
Thus;
σ = (17 × 10^(-6))/(180 × 10^(-4))
σ = 0.944 × 10^(-3) C/m²
Also, the electric field is given by the formula;
E = σ/ε_o
E = (0.944 × 10^(-3))/(8.85 × 10^(-12))
E = 1.067 × 10^(8) N/C
Now, the formula for electric flux for uniform electric field is given as;
Φ = EAcos θ
Where A = πr² = π × 0.03² = 9π × 10^(-4) m²
Thus;
Φ = 1.067 × 10^(8) × 9π × 10^(-4) × cos 4
Φ = 30.095 × 10⁴ N.m²/C